Answer and Explanation:
Reliability is important because if the service lacks lacks reliability this could mean losing a packet or acknowledgement which then requires retransmission.
Delay can be tolerable in different degrees by applications, for example online chatting or conferences need to have the minimum delay possible.
Jitter is the variation in delay for packets belonging to the same flow.
High Jitter: difference between delays is large
Low jitter: difference between delays is small.
Bandwidth depends on the application. In video conferences, for example, there is a need to send million of bits per second to refresh a colour screen while sending a email may not reach even a million.
When two tables share the same primary key, they share a
A. one-to-one relationship.
Explanation:
- One-to-one relationship is a type of cardinality that refers to the relationship between two entities A and B in which one element of A may only be linked to one element of B, or the opposite way.
- A one-to-one relationship in a relational database occurs when one parent record or field has either zero or one child record only.
- These relationships are the easiest to represent in databases because both the parent and child records may be in the same table.
- One-to-one relationships associate one record in one table with a single record in the other table.
- These relationships are frequently used to indicate critical relationships so you can get the data you need to run your business.
- A one-to-one relationship is a link between the information in two tables, where each record in each table only appears once.
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Answer:
a) 179 segments
b) 28 segments
Explanation:
Given data :
A) Round trip time = 100 ms, Timeout = 101 ms
number of segments for round trip = 3000/100 = 30 segments
number of segments for timeout = 15000/100 = 150 segments
total number of segments = 150 + 30 = 180
segments that get re-transmitted under A
Total segments - timeout = 180 - 101 = 179 segments
B) Round trip = 100 ms Timeout = 152 ms
number of segments for round trip = 3000/100 = 30 segments
number of segments for timeout = 15000/100 = 150 segments
total segments = 150 + 30 = 180
segments that get re-transmitted under B
total segments - timeout = 180 - 152 = 28 segments