Question

A spinner has the numbers 11-20 on it. What is the probability that it will land on a multiple of 3?

Answer 1

Answer:

$P(A) = \frac{3}{10}$

Step-by-step explanation:

Given

$S = \{11,12,13,14,15,16,17,18,19,20\}$

Required

The probability of having a multiple of 3

Let the event of having a multiple of 3 be represented as: A

So:

$A = \{12,15,18\}$

$n(A) = 3$

So, the probability is:

$P(A) = \frac{n(A)}{n(S)}$

Where

$n(S) = 10$ i.e. the sample size

So:

$P(A) = \frac{n(A)}{n(S)}$

$P(A) = \frac{3}{10}$