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2 years ago

A person is 89-93 pounds depending on the day, 13 years old, and 5 foot tall. Is this an appropriate weight?

Mathematics

2 answers:

kenny6666 [7]2 years ago

6 0

Answer:

I don't think so cause average in my town is 100 to 109

Angelina_Jolie [31]2 years ago

6 0

Answer:

I don't think so

Step-by-step explanation:

¯\_(ツ)_/ i can't tell you

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3 years ago

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The diameter of a circle is 34 millimeters. What is the circle's area?<br> Use 3.14 for .

icang [17]

Answer:

907.46 mm2

Step-by-step explanation:

Area of circle = (¶d^2)/4

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3 years ago

Surface integrals using an explicit description. Evaluate the surface integral \iint_{S}^{}f(x,y,z)dS using an explicit represen

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Parameterize $S$ by the vector function

$\vec r(x,y)=x\,\vec\imath+y\,\vec\jmath+f(x,y)\,\vec k$

so that the normal vector to $S$ is given by

$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=\left(\vec\imath+\dfrac{\partial f}{\partial x}\,\vec k\right)\times\left(\vec\jmath+\dfrac{\partial f}{\partial y}\,\vec k\right)=-\dfrac{\partial f}{\partial x}\vec\imath-\dfrac{\partial f}{\partial y}\vec\jmath+\vec k$

with magnitude

$\left\|\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}\right\|=\sqrt{\left(\dfrac{\partial f}{\partial x}\right)^2+\left(\dfrac{\partial f}{\partial y}\right)^2+1}$

In this case, the normal vector is

$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=-\dfrac{\partial(8-x-2y)}{\partial x}\,\vec\imath-\dfrac{\partial(8-x-2y)}{\partial y}\,\vec\jmath+\vec k=\vec\imath+2\,\vec\jmath+\vec k$

with magnitude $\sqrt{1^2+2^2+1^2}=\sqrt6$ . The integral of $f(x,y,z)=e^z$ over $S$ is then

$\displaystyle\iint_Se^z\,\mathrm d\Sigma=\sqrt6\iint_Te^{8-x-2y}\,\mathrm dy\,\mathrm dx$

where $T$ is the region in the $x,y$ plane over which $S$ is defined. In this case, it's the triangle in the plane $z=0$ which we can capture with $0\le x\le8$ and $0\le y\le\frac{8-x}2$ , so that we have

$\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}$

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2 years ago

Simplify (9x + 10) - (7x + 8)

Ilia_Sergeevich [38]

Answer:

2x+2

Step-by-step explanation:

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3 years ago

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3 years ago

A person is 89-93 pounds depending on the day, 13 years old, and 5 foot tall. Is this an appropriate weight?​

A person is 89-93 pounds depending on the day, 13 years old, and 5 foot tall. Is this an appropriate weight?