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Ivan
2 years ago
11

Consider the inequality x<1. Determine whether each value of x makes the inequality trueSelect Yes or No va Yes No 3/2 13/6

Mathematics
1 answer:
Degger [83]2 years ago
8 0
He’s right he’s right he’s right
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T^12 x T^10= T to the power of what
coldgirl [10]
  • <em>Answer:</em>

<em>t²²</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there !</em>

<em>t¹²ₓ t¹⁰ = t¹²⁺¹⁰ = t²²</em>

<em>Good luck !</em>

7 0
3 years ago
Read 2 more answers
Find a quadratic polynomial whose sum and and product is -7 and -2
vampirchik [111]

Answer:

<h2>x²+7x-2 = 0</h2>

Step-by-step explanation:

The general form of a quadratic equation with roots a and b is expressed as shown;

x²-(sum of root) x + (product of roots) = 0

x² - (a+b)x + ab = 0 ... 1

Given the sum of roots a+b = -7

Product of roots ab = -2

Substituting this values in equation 1 above wil give;

x²-(-7)x+(-2) = 0

x²+7x-2 = 0

The resulting quadratic polynomial is x²+7x-2 = 0

3 0
3 years ago
What is the measurement of ABC?<br> D. 1180<br> A. 28°<br> ОО<br> E. 208°<br> B. 62°<br> O c. 90°
Len [333]

Answer:

118°

Step-by-step explanation:

Line b is a perpendicular bisector so 90°+28°=118°

7 0
3 years ago
Find the distance between the given points. Round to the nearest tenth. 5,-2 and 1,2.
borishaifa [10]

Answer:

4\sqrt{2}

Step-by-step explanation:

Use the distance equation

\sqrt{(x1-x2)^2+(y1-y2)^2}

insert values (5,-2)=(x1,y1) and (1,2)=(x2,y2)

\sqrt{(5-1)^2+((-2)-2)^2}

\sqrt{16+16}

4\sqrt{2}

Hope that helps :)

3 0
2 years ago
Aggh please help with this
docker41 [41]
Sure ill help you what you need help with
6 0
3 years ago
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