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Dimas [21]
3 years ago
8

Which data set has a variation, or mean absolute deviation, similar to the data set in the given dot plot?​

Mathematics
1 answer:
NISA [10]3 years ago
3 0

Answer:Según el mito griego, Perseo era un semidiós, hijo de Zeus y de la mortal Dánae. ... La Medusa era un monstruo que convertía en piedra a todo el que la mirase, por lo que Perseo utilizó el escudo como espejo para no mirar a Medusa directamente y así alcanzó a cortar la cabeza de la gorgona

Step-by-step explanation:

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30 1/4% as a fraction in simplest
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30 1/4% = 30.25/100 = 3025/10000 = 121/400
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The volume of a cube depends on the length of its sides. This can be written in function notation as v(s). What is the best inte
stellarik [79]

Let

s--------> the length side of the cube

we know that

the volume of the cube is equal to

V(s)= s^{3}

if the length side s is equal to 2\ feet

then

s=2\ feet

and the volume is equal to

V(2)= 2^{3}

V(2)= 8\ feet^{3}

therefore

<u>the answer is the option</u>

D. A cube with side lengths of 2 feet has a volume of 8 cubic feet.

5 0
3 years ago
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What is the equivalent ratio to 16 56​
julia-pushkina [17]

Answer:

The number 2

Step-by-step explanation:

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Which of the following graphs shows the solution set for the inequality below? 3|x + 1| &lt; 9
Bas_tet [7]

Step-by-step explanation:

The absolute value function is a well known piecewise function (a function defined by multiple subfunctions) that is described mathematically as

                                 f(x) \ = \ |x| \ = \ \left\{\left\begin{array}{ccc}x, \ \text{if} \ x \ \geq \ 0 \\ \\ -x, \ \text{if} \ x \ < \ 0\end{array}\right\}.

This definition of the absolute function can be explained geometrically to be similar to the straight line   \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  , however, when the value of x is negative, the range of the function remains positive. In other words, the segment of the line  \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  where \textbf{\textit{x}} \ < \ 0 (shown as the orange dotted line), the segment of the line is reflected across the <em>x</em>-axis.

First, we simplify the expression.

                                             3\left|x \ + \ 1 \right| \ < \ 9 \\ \\ \\\-\hspace{0.2cm} \left|x \ + \ 1 \right| \ < \ 3.

We, now, can simply visualise the straight line,  y \ = \ x \ + \ 1 , as a line having its y-intercept at the point  (0, \ 1) and its <em>x</em>-intercept at the point (-1, \ 0). Then, imagine that the segment of the line where x \ < \ 0 to be reflected along the <em>x</em>-axis, and you get the graph of the absolute function y \ = \ \left|x \ + \ 1 \right|.

Consider the inequality

                                                    \left|x \ + \ 1 \right| \ < \ 3,

this statement can actually be conceptualise as the question

            ``\text{For what \textbf{values of \textit{x}} will the absolute function \textbf{be less than 3}}".

Algebraically, we can solve this inequality by breaking the function into two different subfunctions (according to the definition above).

  • Case 1 (when x \ \geq \ 0)

                                                x \ + \ 1 \ < \ 3 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 3 \ - \ 1 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 2

  • Case 2 (when x \ < \ 0)

                                            -(x \ + \ 1) \ < \ 3 \\ \\ \\ \-\hspace{0.15cm} -x \ - \ 1 \ < \ 3 \\ \\ \\ \-\hspace{1cm} -x \ < \ 3 \ + \ 1 \\ \\ \\ \-\hspace{1cm} -x \ < \ 4 \\ \\ \\ \-\hspace{1.5cm} x \ > \ -4

           *remember to flip the inequality sign when multiplying or dividing by

            negative numbers on both sides of the statement.

Therefore, the values of <em>x</em> that satisfy this inequality lie within the interval

                                                     -4 \ < \ x \ < \ 2.

Similarly, on the real number line, the interval is shown below.

The use of open circles (as in the graph) indicates that the interval highlighted on the number line does not include its boundary value (-4 and 2) since the inequality is expressed as "less than", but not "less than or equal to". Contrastingly, close circles (circles that are coloured) show the inclusivity of the boundary values of the inequality.

3 0
3 years ago
I have 100 msrble the ratio of redto blue is 8:4 how many blue marbles​
azamat

Answer:

This question is not possible

Step-by-step explanation:

7 0
3 years ago
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