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3 years ago

ANSWER QUICK PLEASE!!!! BRAIN LIST AND POINTS

Mathematics

1 answer:

wel3 years ago

8 0

Answer:

x = 9

Step-by-step explanation:

The two angles are alternate exterior and has same measurement

15(x+1) = 150 divide both sides by 15

x + 1 = 10 subtract 1 from both sides

x = 9

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Find sin(a)&cos(B), tan(a)&cot(B), and sec(a)&csc(B).

Reil [10]

Answer:

Part A) $sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}$

Part B) $tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) $sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}$

Step-by-step explanation:

Part A) Find $sin(\alpha)\ and\ cos(\beta)$

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$sin(\alpha)=cos(\beta)$

Find the value of $sin(\alpha)$ in the right triangle of the figure

$sin(\alpha)=\frac{8}{14}$ ---> opposite side divided by the hypotenuse

simplify

$sin(\alpha)=\frac{4}{7}$

therefore

$sin(\alpha)=\frac{4}{7}$

$cos(\beta)=\frac{4}{7}$

Part B) Find $tan(\alpha)\ and\ cot(\beta)$

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$tan(\alpha)=cot(\beta)$

<em>Find the value of the length side adjacent to the angle alpha</em>

Applying the Pythagorean Theorem

Let

x ----> length side adjacent to angle alpha

$14^2=x^2+8^2\\x^2=14^2-8^2\\x^2=132$

$x=\sqrt{132}\ units$

simplify

$x=2\sqrt{33}\ units$

Find the value of $tan(\alpha)$ in the right triangle of the figure

$tan(\alpha)=\frac{8}{2\sqrt{33}}$ ---> opposite side divided by the adjacent side angle alpha

simplify

$tan(\alpha)=\frac{4}{\sqrt{33}}$

therefore

$tan(\alpha)=\frac{4}{\sqrt{33}}$

$tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) Find $sec(\alpha)\ and\ csc(\beta)$

we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$sec(\alpha)=csc(\beta)$

Find the value of $sec(\alpha)$ in the right triangle of the figure

$sec(\alpha)=\frac{1}{cos(\alpha)}$

Find the value of $cos(\alpha)$

$cos(\alpha)=\frac{2\sqrt{33}}{14}$ ---> adjacent side divided by the hypotenuse

simplify

$cos(\alpha)=\frac{\sqrt{33}}{7}$

therefore

$sec(\alpha)=\frac{7}{\sqrt{33}}$

$csc(\beta)=\frac{7}{\sqrt{33}}$

6 0

3 years ago

ANSWER ASAPP!!!!!!FAST PLZZZZZZ!!!!!!!!!

faltersainse [42]

The answer to your question is c

5 0

3 years ago

Read 2 more answers

A survey of 25 grocery stores revealed that the mean price of a gallon of milk was $2.98, with a standard error of $0.10. What i

Gnesinka [82]

Answer:

95% confidence interval: (2.784,3.176)

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 25

Sample mean = $2.98

Standard error = $0.10

Alpha = 0.05

95% confidence interval:

$\mu \pm z_{critical}(\text{Standard error})$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$2.98 \pm 1.96(0.10) = 2.98 \pm 0.196 = (2.784,3.176)$

5 0

3 years ago

The bases of a trapezoid are 16.8 yards and 6.9 yards. If the height is 2 yards, what is the area of the trapezoid?

Svet_ta [14]

Hello,
Here is the formula to find the area of the trapezoid:
A=1/2(b1+b2)×h
Where b1 represent big base
b2 represent small base
and h represent height
Now, we just need to replace the number to get the final answer:
A=1/2(16.8+6.9)×2
A=1/2(23.7)×2
A=23.7 square yards. As a result, the area of the trapezoid is 23.7 square yards. Hope it help!

8 0

3 years ago

Help me please I don't know how to do this.

djyliett [7]

Hey there.

If the decimal point is .500 and up, we will be rounding up. If it is .499 and lower, we will be rounding down.
Now let’s look at the numbers.
2.500 g can be rounded up, so we’ll make that 3.000 g.
5.000 g is going to stay the same, since the decimal point is .000
2.268 g will be rounded down, making it 2.000 g
5.670 will be rounded up and will become 6.000 g
And finally, 11.340 g will be rounded down to 11.000 g.

Hope this helps!

3 0

3 years ago