What this question simply asks about is you write the numbers it gave you in only one digit by 10 to the power of n. Where n represents the number of shifts of the decimal point.
And to get this number to be one digit, then you have to approximate.
To approximate; you should always consider that less than 5 counts zero and 5 or more counts+1.
Example:
5.3 is approximately 5
5.5 is approx. 6
5.9 is also approx. 6
and so on.
So the final answers are;
1) 4*10^13
2) 5*10^-11
Please note that 10^positive integer will cause the decimal point to move to the right which means a number greater than 1, usually, while 10^negative integer means number smaller than 1, usually.
Hope this helps.
Answer:
<h3>46.</h3>
<u>Total number in favour:</u>
<u>Probability:</u>
- P(favour, A) = 128/224 = 4/7
<h3>47.</h3>
<u>Total number in against:</u>
<u>Probability:</u>
- P(against, not B) = 32/80 = 2/5
Step-by-step explanation:
64 bro
