Answer:
m < A = 60º
m < B = 30º
Step-by-step explanation:
The given sides on this triangle are: 6, , and 12
Any triangle with the angles of 30º - 60º - 90º always has side lengths in this proportion:
x, , 2x
We can line this up with the given sides. If x is 6, then 2x would be 12.
x : : 2x = 6 : : 12
Angle B is across from 6, the shortest side. That also means that it corresponds to x, or the smallest angle in the proportion, 30º.
m < B = 30º
Solving for < A:
Method 1) Sum of Angles in a Triangle
Since we already know that one angle is right and therefore 90º and m < B is 30º, we can subtract these from the total sum of angle measures in a triangle to get the last angle, < A.
180º - 90º - 30º = 60º
m < A = 60º
Method 2) Using the second part of the proportion
Since m < A is across from the second largest side, we know that it is equal to ( in this question) or 60º in the angle proportion.
This means that m < A = 60º
Let me know if you have any questions!
Answer:
All Real Numbers
Step-by-step explanation:
Step 1:
3x - 9 = 3 ( x - 3 ) Equation
Step 2:
3x - 9 = 3x - 9 Multiply
Step 3:
- 9 = - 9 Subtract 3x on both sides
Answer:
All Real Numbers
Hope This Helps :)
Answer:
<u>The measure of the arc CD = 64°</u>
Step-by-step explanation:
It is required to find the measure of the arc CD in degrees.
So, as shown at the graph
BE and AD are are diameters of circle P
And ∠APE is a right angle ⇒ ∠APE = 90°
So, BE⊥AD
And so, ∠BPE = 90° ⇒(1)
But it is given: ∠BPE = (33k-9)° ⇒(2)
From (1) and (2)
∴ 33k - 9 = 90
∴ 33k = 90 + 9 = 99
∴ k = 99/33 = 3
The measure of the arc CD = ∠CPD = 20k + 4
By substitution with k
<u>∴ The measure of the arc CD = 20*3 + 4 = 60 + 4 = 64°</u>
i think it’s is a for the first one
Answer:
you would need 4 matts
Step-by-step explanation: