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3 years ago

What is the length of the hypotenuse?

Mathematics

1 answer:

gayaneshka [121]3 years ago

5 0

Answer:

Hello! answer: 5

Step-by-step explanation:

What you do to find the answer for these is do a^2+b^2=c^2 Basically meaning 4 × 4 + 3 × 3 will equal a number that you then find the suare root of square root just meaning a number multiplied by itself to equals that number so...

4 × 4 = 16

3 × 3 = 9

16 + 9 = 25

√25 = 5

5 × 5 = 25 therefore c = 5 hope that helps!

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Square root of 3 because it equals 1.73

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3 years ago

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Zoe has 1500 bees Zoe wants to make six friendship bracelet she needs do you want jeep 15 beads for each bracelet how many beads

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4 years ago

Which of the following can be concluded given Z1 a ZT?<br> 4<br> 3/2<br> 5<br> a

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4 years ago

The following are weights in pounds of a college sports team: 165, 171, 174, 180, 182, 188, 189, 192, 198, 202, 202, 225, 228, 2

babunello [35]

Answer:

There are no values in the data that is two standard deviations below the mean.

Step-by-step explanation:

We are given the following data set in question:

165, 171, 174, 180, 182, 188, 189, 192, 198, 202, 202, 225, 228, 235, 240

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{2971}{15} = 198.06$

The mean of sample is 198.06 pounds.

Sum of squares of differences = 7984.93

$S.D = \sqrt{\dfrac{7984.93}{14}} = 23.88$

The sample standard deviation is 23.88 pounds.

We have to find the weight that is 2 standard deviations below the mean.

$x < \bar{x}- 2s\\x < 198.06 -2(23.88)\\x < 150.3$

Thus, we have to find a value less than 150.3.

Sorted data: 165, 171, 174, 180, 182, 188, 189, 192, 198, 202, 202, 225, 228, 235, 240

There are no values in the data that is less than 150.3

4 0

4 years ago

What is the equation of the quadratic graph with a focus of (-4, 17/8) and a directrix of y=15/8

MrRa [10]

Yay

so
this is going to be
(x-h)^2=4p(y-k)

(h,k) is the vertex
p is the distance from the vertex to the focus and the vertex to directix

half of the distance between directix and focus is p
if the directix is above the focus, p is negative
if the directix is below the focus, p is positive
so

we see
y=15/8 is the directix
focus is above directix (p is positive)
it is 2/8 or 1/4 above it
so
half of 1/4 is 1/8
p=1/8
the vertex is 1/8 below vertex so it is it at (-4,16/8) or (-4,2)
the equation is
(x-(-4))^2=4(1/8)(y-2) or
(x+4)^2=4(1/8)(y-2) is the equation

6 0

3 years ago