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3 years ago

Which scatter plot shows a nonlinear association for the data

Mathematics

2 answers:

Vedmedyk [2.9K]3 years ago

6 0

Answer:

bottom left

Step-by-step explanation:

givi [52]3 years ago

6 0

Answer:

Step-by-step explanation:

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The figure in the picture is made up of 5 congruent squares. If the perimeter of the entire figure is 21.6 cm, find its area.

vovikov84 [41]

Perimeter is length plus width so use that to help you

3 0

3 years ago

Graph the equation 2(y+3)<4x

myrzilka [38]

Answer:

y<2x-3

Step-by-step explanation:

2(y+3)<4x

2y+6<4x

-6 -6

2y<4x-6

÷2 ÷2

y<2x-3

5 0

3 years ago

Suppose that an account earns 5.9% interest and after 2 years the balance is $ 4472. Find the principal that was invested. Use

Marizza181 [45]

Answer:

The principle amount = $4000

Step-by-step explanation:

Formula:

Simple interest I = PTR/100

P - Principle amount

T - Number of years

R - Rate of interest

<u>To find principle amount</u>

Here , P = ?, T = 2 years, R = 5.9% and p + I = $4472

I = PTR/100

P + (P*2**5.9)/100 = 4472

P[1 + 11.8/100] = 4472

P[111.8/100] = 4472

P = (4472*100)/111.8 = 4000

Therefore the principle amount P = $4000

7 0

3 years ago

Help plzzz I'm almost done

iren2701 [21]

Step-by-step explanation:

7 and 4 are solutions the others not

8 0

3 years ago

A tourist first walked 17km with a speed of v km/h. Then he hiked 12 km uphill with the speed that was 2 km/hour less than his o

ExtremeBDS [4]

Answer: $t=\frac{17}{v}+\frac{12}{v-2}$

Step-by-step explanation:

Given: A tourist first walked 17km with a speed of v km/h.

Since $Speed=\frac{distance}{time}$

therefore, $Time=\frac{distance}{speed}$

Let $t_1$ be the time he walked with speed v.

then $t_1=\frac{17}{v}$

Also he hiked 12 km uphill with the speed that was 2 km/hour less than his original speed.

Let $t_2$ be the time he hiked 12 km,

Then $t_2=\frac{12}{v-2}$

The total time for the whole trip is given by:-

$t=t_1+t_2=$

Substitute the values of $t_1$ and $t_2$ in the equation, we get

$t=\frac{17}{v}+\frac{12}{v-2}$

4 0

4 years ago