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Pachacha [2.7K]
3 years ago
7

How many significant figures are in 0.0624000?

Mathematics
1 answer:
Dafna11 [192]3 years ago
4 0

Answer:

Use notes and youll get an answer

Step-by-step explanation:

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Question 2 (4 points)
Yakvenalex [24]
The answer is a. y=3/4x + 4
3 0
3 years ago
A tub is filled with 18000 cm3 of water. It loses one-tenth of its water every 12 hours. What volume of water would be remaining
Lina20 [59]

Answer:

0 cm³

Step-by-step explanation:

the lost of water =

(5×24)/12 x 1/10 × 18000

= 10/10 × 18000 = 18,000 cm³

so, the remaining water in the tub=

18,000 - 18,000 = 0 cm³

(the tub is empty)

6 0
3 years ago
Find the equation line through point (-4,15) and (4,-5)
Oduvanchick [21]
Answer highlighted in blue. Hope this helps.
8 0
3 years ago
X^3+9X^2–25X–33=0<br> Find The root of X??
Simora [160]

Answer:

x=-11, -1, and 3

Step-by-step explanation:

x^3+9x^2-25x-33=0

There are formulas to solve cubics, but that probably is not the way you are expected to go.  Here is a trial and error approach that works in this case.

Assume that the cubic can be factored and that the roots are r1, r2, and r3.  Then the factored form is

(x-r1)(x-r2)(x-r3)=0

This shows that the constant must equal the product of the roots.

(r1)(r2)(r3)=-33

One possibility is that the roots are integers.  In this case, a factor of 33 might work.  Prime factorization of 33 gives 3 and 11.  Try 3.  Then (x-3) is a factor.

Divide the cubic by (x-3).  It works. the result is

x^2+12x+11

This has factors of (x+11) and (x+1).  Therefore, the roots are 3, -1, and -11

6 0
3 years ago
Three consecutive odd integers have a sum of 33
KATRIN_1 [288]
Three consecutive integers that add up to 33 are 2 above and lower than a middle number.  This means that the average of these 3 numbers will be the same.  Therefore, 33/3=11 as the average.  Therefore 11 is the middle number, 9 is 2 below (a consecutive odd integer) and 13 is 2 above (a third consecutive odd integer).  Therefore the 3 numbers are 9, 11, and 13.
4 0
3 years ago
Read 2 more answers
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