Answer:
Rate of change and slope is the same since they are both terms of every rate, but rate of change can be said in any terms as in exponential and linear, etc. While slopes are only for linear equations.
Step-by-step explanation:
Hope this helps :)
B. Negative describes the line because it is sloping downwards.
Answer:
<h2><u><em>
2 × [(3x² + x + 2) + (-x² – 5x + 1)] =</em></u></h2>
Step-by-step explanation:
Write an expression for the perimeter of a rectangle with a length of
(3x² + x + 2) and a width of (-x² – 5x + 1).
P = 2 × (L + W)
<u><em>2 × [(3x² + x + 2) + (-x² – 5x + 1)] =</em></u>
if you want the result:
4x²−8x+6
Answer:
∠MLP = 72° , ∠LJK = 22° , ∠JKL = 72° , ∠KLJ = 86°
Step-by-step explanation:
Here, given In ΔJLK and ΔMLP
Here, JK II ML, LM = MP
∠JLM = 22° and ∠LMP = 36°
Now, As angles opposite to equal sides are equal.
⇒ ∠MLP = ∠MPL = x°
Now, in ΔMLP
By <u>ANGLE SUM PROPERTY</u>: ∠MLP + ∠MPL + ∠LMP = 180°
⇒ x° + x° + 36° = 180°
⇒ 2 x = 180 - 36 = 144
or, x = 72°
⇒ ∠MLP = ∠MPL = 72°
Now,as JK II ML
⇒ ∠LJK = ∠JLM = 22° ( Alternate pair of angles)
Now, by the measure of straight angle:
∠MLP + ∠JLM + ∠JLK = 180° ( Straight angle)
⇒ 72° + 22° + ∠JLK = 180°
or, ∠JLK = 86°
In , in ΔJLK
By <u>ANGLE SUM PROPERTY</u>: ∠JKL + ∠JLK + ∠LJK = 180°
⇒ ∠JKL + 86° + 22° = 180°
⇒ ∠JKL = 180 - 108 = 72 , or ∠JKL = 72°
Hence, from above proof , ∠MLP = 72° , ∠LJK = 22° , ∠JKL = 72° ,
∠KLJ = 86°
136 + x = 189
-136 -136
x = 53
Arthur must earn $53 in the next week to buy the new coat.
