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fenix001 [56]
3 years ago
12

What is 2x+4y=8 as a slope

Mathematics
1 answer:
saveliy_v [14]3 years ago
8 0

Answer:

2x + 4y = 8 \\ 4y =  - 2x + 8 \\ y =  -  \frac{1}{2} x + 2 \\ from \: general \: equation \: of \: line \\ y = mx + c \\ and \: m \: is \: the \: gradient \: or \: slope \\ by \: relation \: with \:  \: y =  -  \frac{1}{2} x + 2 \\ slope \:  =  -  \frac{1}{2}

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What is the slope and Unit Rate for the graph?
balandron [24]
I think it's y=1x+4.75
6 0
3 years ago
A survey conducted by the Consumer Reports National Research Center reported, among other things, that women spend an average of
Nookie1986 [14]

Answer:

(a) The probability that a randomly selected woman shop exactly two hours online is 0.217.

(b) The probability that a randomly selected woman shop 4 or more hours online is 0.0338.

(c) The probability that a randomly selected woman shop less than 5 hours online is 0.9922.

Step-by-step explanation:

Let <em>X</em> = time spent per week shopping online.

It is provided that the random variable <em>X</em> follows a Poisson distribution.

The probability function of a Poisson distribution is:

P (X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0,1,2,...

The average time spent per week shopping online is, <em>λ </em>= 1.2.

(a)

Compute the probability that a randomly selected woman shop exactly two hours online over a one-week period as follows:

P (X=2)=\frac{e^{1.2}(1.2)^{2}}{2!} =0.21686\approx0.217

Thus, the probability that a randomly selected woman shop exactly two hours online is 0.217.

(b)

Compute the probability that a randomly selected woman shop 4 or more hours online over a one-week period as follows:

P (X ≥ 4) = 1 - P (X < 4)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

              =1-\frac{e^{1.2}(1.2)^{0}}{0!}-\frac{e^{1.2}(1.2)^{1}}{1!}-\frac{e^{1.2}(1.2)^{2}}{2!}-\frac{e^{1.2}(1.2)^{2}}{3!}\\=1-0.3012-0.3614-0.2169-0.0867\\=0.0338

Thus, the probability that a randomly selected woman shop 4 or more hours online is 0.0338.

(c)

Compute the probability that a randomly selected woman shop less than 5 hours online over a one-week period as follows:

P (X < 5) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)

              =\frac{e^{1.2}(1.2)^{0}}{0!}+\frac{e^{1.2}(1.2)^{1}}{1!}+\frac{e^{1.2}(1.2)^{2}}{2!}+\frac{e^{1.2}(1.2)^{3}}{3!}+\frac{e^{1.2}(1.2)^{4}}{4!}\\=0.3012+0.3614+0.2169+0.0867+0.0260\\=0.9922

Thus, the probability that a randomly selected woman shop less than 5 hours online is 0.9922.

8 0
4 years ago
Seven less than a third of the sum of a number and two​
elena-s [515]

The number is 15.

   2x/3-7=3

   3(2x/3–7)=3×3

   2x-21+21=9+21

   2x/2=30/2

   x=15

Proof

   15×2=30

   30/3=10

   10–7=3

3 0
3 years ago
what is the approximate distance from one corner of the soccer field to the opposite corner 60 yards, 100 yards
aalyn [17]

Answer:

Using Pythagorean theorem:

Diagonal = sqrt( 60^2 + 100^2) = 116.62

Hope this helps!

:)

7 0
3 years ago
Kayla and Josh are watching marathons of their favorite TV show. Episodes of Kayla's show are 120 minutes long, while episodes o
zhannawk [14.2K]

9514 1404 393

Answer:

  1080 minutes

Step-by-step explanation:

The greatest common factor (GCF) of the two times is 15 minutes, so their least common multiple is (120×135)/15 = 1080 minutes.

In that time, Kayla will have watched 9 shows, and Josh will have watched 8.

It will be 1080 minutes before they start again at the same time.

6 0
3 years ago
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