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3 years ago

What is the value of 3x^2 + 4y^2 if x = 2 y = 1

Mathematics

2 answers:

Ahat [919]3 years ago

6 0

Answer:

16 is answer

Step-by-step explanation:

3(2)^2+4(1)^2= 3(4)+4(1)=12+4=16

Crank3 years ago

5 0

The answer to this question is 16.

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Answer:

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Step-by-step explanation:

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What is the equation of the circle with center (4, 4) that passes through the point (10, 14)? HELP MEEEEE PLEASE

Gemiola [76]

Answer:

The equation of the circle can be written as:

$\left(x-4\right)^2+\left(y-4\right)^2=136$

Step-by-step explanation:

The general equation of a circle with center $(h,k)$ and radius $r$ is:

$\left(x-h\right)^2+\left(y-k\right)^2=r^2$

In our example, we know $\left(h,k\right)=\left(4,4\right)$ , as we just have to make sure we need determine $\:r^2$ .

$\left(x-4\right)^2+\left(y-4\right)^2=r^2\:\:$

As the circle passes through (10, 14), that pair of values for x and y must satisfy the equation. So we have:

$\left(10-4\right)^2+\left(14-4\right)^2=r^2$

$\mathrm{Switch\:sides}$

$r^2=\left(10-4\right)^2+\left(14-4\right)^2$

$r^2=6^2+10^2$

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Thus the equation of the circle can be written as:

$\left(x-4\right)^2+\left(y-4\right)^2=136$

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