Using a graphic tool.
<span>see attached graphic</span>
<span>
the solutions are
x1=-2
x2=0.811
</span>check
for x=-2
x^4+3x^3+3x2-3x-4
(-2) ^4+3(-2) ^3+3(-2) ^2-4=16+(-24)+12-4=0 ok
For x=0.811
(0.811) ^4+3(0.811) ^3+3(0.811) ^2-4=0.4326+(1.6002)+1.9731-4=0 ok
Answer:
B.
Step-by-step explanation:
First angle 1 and 2 add up to 180 and then angle 2 and 3 also add up to 180. So angle 2 is common hence both are congruent to each other.
Answer:
<u>ALTERNATIVE 1</u>
a. Find the profit function in terms of x.
P(x) = R(x) - C(x)
P(x) = (-60x² + 275x) - (50000 + 30x)
P(x) = -60x² + 245x - 50000
b. Find the marginal cost as a function of x.
C(x) = 50000 + 30x
C'(x) = 0 + 30 = 30
c. Find the revenue function in terms of x.
R(x) = x · p
R(x) = x · (275 - 60x)
R(x) = -60x² + 275x
d. Find the marginal revenue function in terms of x.
R'(x) = (-60 · 2x) + 275
R'(x) = -120x + 275
The answers do not make a lot of sense, specially the profit and marginal revenue functions. I believe that the question was not copied correctly and the price function should be p = 275 - x/60
<u>ALTERNATIVE 2</u>
a. Find the profit function in terms of x.
P(x) = R(x) - C(x)
P(x) = (-x²/60 + 275x) - (50000 + 30x)
P(x) = -x²/60 + 245x - 50000
b. Find the marginal cost as a function of x.
C(x) = 50000 + 30x
C'(x) = 0 + 30 = 30
c. Find the revenue function in terms of x.
R(x) = x · p
R(x) = x · (275 - x/60)
R(x) = -x²/60 + 275x
d. Find the marginal revenue function in terms of x.
R(x) = -x²/60 + 275x
R'(x) = -x/30 + 275
They are equivalent because when you distribute the -0.5 into 3x+5 you get the expression -1.5x+2.5
The two rolls of the number cube are independent events because
the result of 1 roll does not affect the result of the other roll.
To find the probability of two independent events, we first find
the probability of each event, then we multiply the probabilities.
We can find the probability of an event using the following ratio:
number of favorable outcomes/total number of outcomes
Since there is only one way to roll a 3 and there are six
possible outcomes, 1, 2, 3, 4, 5, and 6, the probability of rolling a 3 is 1/6.
Since there is also only one way to roll a 2 and there are
six possible outcomes, the probability of rolling a 2 would be 1/6.
Now we multiply the probabilities.
1/6 x 1/6 is 1/36.
So the probability of rolling a 3 and a 2 is 1/36.
