(734 ÷ u ) - 255 For u =2.
2 answers:
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Answer:
True
Step-by-step explanation:
Lines in three dimensions can be one of ...
- coincident
- parallel
- intersecting (at one point)
- skew
Lines are coplanar when a plane can be defined that includes the entirety of both of them. In the attached image, lines m₁ and n intersect and both lie in the gray plane. They are coplanar.
Lines m and m₁ are parallel, and both are contained in the turquoise plane. They are coplanar. A plane can always be drawn that will contain a pair of parallel lines. That is, any two parallel lines must be coplanar.
The lines m and n in the figure are <em>skew</em>, non-intersecting and non-parallel. They cannot be contained in a single plane.
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<em>Additional comment</em>
Three or more parallel lines may not be coplanar. They will only definitely be coplanar when considered in pairs.
Answer:
The value of y is
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form or
In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin
In this problem the line passes through the origin
therefore
Is a proportional variation
Find the value of k
with the point
The equation is equal to
so
For
substitute
Answer:
46
Step-by-step explanation:
See attached for reference
<u>The points given:</u>
- (−6, −2), (0, −10), (5, 2), (−1, 10)
They form a rectangle as seen in the picture.
We can notice that this is a parallelogram, as respective lines have same difference of coordinates.
<u>So calculating only the two of the sides will be sufficient to get its perimeter:</u>
- a = √(-1+6)² + (10+2)² = √25+144 = √169= 13
- b = √(0+6)² + (-10+2)² = √36+64 = √100 = 10
<u>So, the perimeter:</u>
- P = 2(13+10) = 46
