D. Aidan’s
The larger the sample size (number of people asked), the more accurate the results generally are, due to the law of large numbers.
? Ummm What is the question???
The first three terms of sequence are 9 , 6 , 3
<em><u>Solution:</u></em>
Given the recursive function f(n) = f(n - 1) - 3
Where f(1) = 9
To find: First three terms of sequence
Substitute n = 2 , n = 3 and n = 4 in given recursive function
When n = 2
f(n) = f(n - 1) - 3
f(2) = f(2 - 1) - 3
f(2) = f(1) - 3
f(2) = 9 - 3 = 6
f(2) = 6
Thus second term is 6
When n = 3
f(3) = f( 3 - 1) - 3
f(3) = f(2) - 3
f(3) = 6 - 3 = 3
f(3) = 3
Thus the third term is 3
When n = 4
f(4) = f( 4 - 1) - 3
f(4) = f(3) - 3
f(4) = 3 - 3
f(4) = 0
Thus the fourth term is 0
Thus first three terms of sequence are 9 , 6 , 3
Answer:
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Step-by-step explanation:
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Answer:y = y = (32 - 6x)/(7 - x)
Step-by-step explanation:
1. Distribute -> 7y - 56 + 24 = xy - 6x
2. Add Like Terms -> 7y - 32 = xy - 6x
3. Collect Like Terms -> 7y - xy = 32 - 6x
4. Factor Out the "y" -> y(7 - x) = 32 - 6x
5. Divide Out the Left "x" -> y = (32 - 6x)/(7 - x)
