Recall the equation relating an object's change in thermal energy to its change in temperature:
ΔQ = mcΔT
ΔQ is the change in thermal energy.
m is the mass of the object.
c is the object's specific heat.
ΔT is the object's change in temperature.
Given values:
m = 0.5 kg = 500g
ΔT = (7-0)⁰C = 7°C
Online sources say the specific heat of silver is 0.240 J/g⁰C
Substitute the terms in the equation with the given values and solve for ΔQ:
ΔQ = 500×0.240×7
<h3>ΔQ = 840 J</h3>
Answer:
Explanation:
Given that,
Half life = 12years
How long does it take to decompose form 655ppbm to 10ppbm.
Rate of decay is given as
Q=Qo• exp(-λt)
at t=0 Qo=655
Then, Q=10
λ is decay rate and it is
λ= In2 / t½
λ= In2/12
λ=0.05776
Therefore,
Q=Qo• exp(-λt)
10=655exp(-0.05776t)
10/655=exp(-0.05776t)
0.01527=exp(-0.05776t)
Take In of both sides
In(0.01527)=-0.05776t
-4.182=-0.05776t
Then, t=-4.182/-0.05776
t=72.4years
Then the time to decay to 10ppbm is 72 years and 3 months
Or 72 years approximately
Twice the momentum as 5 doubled is 10 so it is B
0.32 km
How to reach the answer:
The formula below provides the tsunami's speed in response to the query.
s = 356√d
when the tsunami's speed is 200 km/h, the equation's "s" is changed to "200," and the equation of speed is then expressed as follows.
200 = 356√d
The equation can be changed to compute the depth of the water as,
√d = 200÷356
√d = 0.562
Now on squaring both sides:
(√d)² = (0.562)²
d = (0.562)² = 0.316 or 0.32
Therefore the approximate depth of water for a tsunami travelling at 200km/h is 0.32 km
Know more about speed here:
brainly.com/question/19930939
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