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2 years ago

Is -2/3 and -0.8 greater than, less than, or equal to?

Mathematics

1 answer:

aniked [119]2 years ago

5 0

Answer:

-2/3 is greater than -0.8

Step-by-step explanation:

-2/3 is greater than -0.8. If -2/3 forms to become a decimal it becomes 0.66 (repeated). It is closer to zero therefore causing it to be greater than -0.8.

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How to solve this problem im not getting a good answer

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3 years ago

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Solve and find x 3x+2/4x+1=5x+1/3x+2

horrorfan [7]

Step-by-step explanation:

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2 years ago

Convert the Cartesian equation (x 2 + y 2)2 = 4(x 2 - y 2) to a polar equation.

SashulF [63]

<u>ANSWER</u>

${r}^{2} = 4 \cos2\theta$

<u>EXPLANATION</u>

The Cartesian equation is

${( {x}^{2} + {y}^{2} )}^{2} = 4( {x}^{2} - {y}^{2} )$

We substitute

$x = r \cos( \theta)$

$y = r \sin( \theta)$

and

${x}^{2} + {y}^{2} = {r}^{2}$

This implies that

${( {r}^{2} )}^{2} = 4(( { r \cos\theta) }^{2} - {(r \sin\theta) }^{2} )$

Let us evaluate the exponents to get:

${r}^{4} = 4({ {r}^{2} \cos^{2}\theta } - {r}^{2} \sin^{2}\theta)$

Factor the RHS to get:

${r}^{4} = 4{r}^{2} ({ \cos^{2}\theta } - \sin^{2}\theta)$

Divide through by r²

${r}^{2} = 4 ({ \cos^{2}\theta } - \sin^{2}\theta)$

Apply the double angle identity

$\cos^{2}\theta -\sin^{2}\theta= \cos(2 \theta)$

The polar equation then becomes:

${r}^{2} = 4 \cos2\theta$

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3 years ago

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antiseptic1488 [7]

Answer:

Step-by-step explanation:

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2 years ago

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irina1246 [14]

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3 years ago

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