What are the volume formulas for the listed shapes: Cylinder, Cone and Sphere.

Mathematics

2 answers:

sesenic [268]2 years ago

8 0

Cylinder: V = $\pi r^{2} h$

Cone: V = $\pi r^{2} h /3$

Sphere: V = $4 \pi r^{3} /3$

sashaice [31]2 years ago

7 0

V of cylinder = pie × radius square × height
v of cone =1/3 × pie × radius square × height
v of a sphere = 4× pie × cubic radius all over three

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Of the 58 employees in a firm, 8 are considered support staff, and 7 of the employees have more than five years of experience. A

polet [3.4K]

Using statistical concepts, it is found that the number of outcomes that are possible for the complement of the union of Events J and K is of 43.

<h3>What is the union of events J and K?</h3>

It means that at least one of event J or event K is true, hence, it is composed by employees that are either considered support staff(less than 5 years of experience) or employees that have more than five years of experience, combining a total of 7 + 8 = 15 employees.

<h3>What is the complement?</h3>

The total number of outcomes of the union of J and K, plus the complement, add to the total number of 58, hence:

15 + x = 58

x = 43.

The number of outcomes that are possible for the complement of the union of Events J and K is of 43.

More can be learned about complementary events at brainly.com/question/9752956

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1 year ago

-3( 2u + 5 ) +3.5u = -1u solve the equation

lora16 [44]

Answer:

that conclude idk

Step-by-step explanation:

-6U+-15+3.5U=-1U

-2.5U+15

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3 years ago

What is the equation of a line passing through the points (-3,<br> -2) and (2, 0)?

Lostsunrise [7]

Answer:

$y=0.400x+-0.800$

Step-by-step explanation:

Given the following question:

point A = (-3, -2)
point B = (2, 0)

To write the equation of the line that passes through two points we have to write the points in slope intercept form.

Formula for slope intercept:

$y=mx+b$

M is equal to the slope of the two points, so first we need to fine the slope of the two points.

$(-3,-2)=(x1,y1)$
$(2,0)=(x2,y2)$

$m=\frac{y2-y1}{x2-x1}$
$m=\frac{0--2}{2--3} =\frac{2}{5}$
$m=\frac{2}{5} =0.400$

$y=mx+b$
$y=-2$
$m=0.400$
$x=-3$
$-2=0.400(-3)+b$
$0.400\times-3=-1.20$
$-2+1.2=-0.800$
$b=-0.800$

$y=0.400x+-0.800$

Hope this helps.