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Ede4ka [16]
2 years ago
6

Ms.Gallegos burns 236 calories

Mathematics
1 answer:
Anon25 [30]2 years ago
6 0
Dang so he fat step by step
You might be interested in
kell works at an after-school program at an elementray school. on monday he work for 1.5 hours and recived 12.6 dollars, on tues
Rina8888 [55]

Answer:

Kell would make more money working 10 hours than Markio.

Step-by-step explanation:

To find how much Kell makes per hour, you have to divide how much he worked by how much he earned. So on Monday, Kell worked 1.5 hours and received 12.6 dollars. Divide 12.6/1.5 and you'll find you're answer.

Monday:   12.6/1.5=<u>8.4</u>

On Tuesday, the problem states that he worked 2.5 hours and received 21 dollars. Divide 21/2.5 and you'll find the answer.

Tuesday:     21/2.5= <u>8.4</u>

On Wednesday, the problem states that he worked 4 hours and received 33.60. Divide 33.60/4 and you'll get you're answer.

Wednesday:    33.60/4= <u>8.4</u>

So we can conclude that Kell makes $8.40 per hour.

Now the problem states, Markio gets paid 7 dollars per hour. To find the answer to the question, you have to multiply how much they make per hour times 10 hours.

Markio:  7x10=70

Kell:  8.4x10=84

So to answer the question, Kell would make more money working 10 hours.


Hope it helps!

3 0
2 years ago
Select all ratios equivalent to 3:2.
weeeeeb [17]
So the Correct answer would be all three of them.
This includes 27:18, 12:8, and 21:14.
The math behind this includes proportions.
For instance, if you multiple 3 by 9, you get 37. You have to multiple 2 by 9 now, and you should get 18. This is how all three of the answers are correct!
8 0
3 years ago
Read 2 more answers
jorge needs a string that is 4 feet long .so far his string is 44 inches. is it long enough or dose he need to make it longer
Romashka-Z-Leto [24]

Answer:

longer

Step-by-step explanation:

12 inches is a foot so you need to multiply 12 by 4 which gives you 48 so he needs 4 more inches to have enough string

5 0
3 years ago
Reliance on solid biomass fuel for cooking and heating exposes many children from developing countries to high levels of indoor
castortr0y [4]

Answer:

A) 95% confidence interval for the population mean PEF for children in biomass households = (3.214, 3.386)

95% confidence interval for the population mean PEF for children in LPG households

= (4.125, 4.375)

Simultaneous confidence interval for both = (3.214, 4.375)

B) The result of the hypothesis test is significant, hence, the true average PEF is lower for children in biomass households than it is for children in LPG households.

C) 95% confidence interval for the population mean FEY for children in biomass households = (2.264, 2.336)

Simultaneous confidence interval for both = (2.264, 4.375)

This simultaneous interval cannot be the same as that calculated in (a) above because the sample mean obtained for children in biomass households here (using FEY) is much lower than that obtained using PEF in (a).

Step-by-step explanation:

A) Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the z-distribution. This is because although, there is no information provided for the population standard deviation, the sample sizes are large enough for the sample properties to approximate the population properties.

Finding the critical value from the z-tables,

Significance level for 95% confidence interval

= (100% - 95%)/2 = 2.5% = 0.025

z (0.025) = 1.960 (from the z-tables)

For the children in the biomass households

Sample mean = 3.30

Standard error of the mean = σₓ = (σ/√N)

σ = standard deviation of the sample = 1.20

N = sample size = 755

σₓ = (1.20/√755) = 0.0436724715 = 0.04367

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 3.30 ± (1.960 × 0.04367)

CI = 3.30 ± 0.085598

95% CI = (3.214402, 3.385598)

95% Confidence interval = (3.214, 3.386)

For the children in the LPG households

Sample mean = 4.25

Standard error of the mean = σₓ = (σ/√N)

σ = standard deviation of the sample = 1.75

N = sample size = 750

σₓ = (1.75/√750) = 0.063900965 = 0.063901

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 4.25 ± (1.960 × 0.063901)

CI = 4.25 ± 0.125246

95% CI = (4.12475404, 4.37524596)

95% Confidence interval = (4.125, 4.375)

Simultaneous confidence interval for both = (3.214, 4.375)

B) The null hypothesis usually goes against the claim we are trying to test and would be that the true average PEF for children in biomass households is not lower than that of children in LPG households.

The alternative hypothesis confirms the claim we are testing and is that the true average PEF is lower for children in biomass households than it is for children in LPG households.

Mathematically, if the true average PEF for children in biomass households is μ₁, the true average PEF for children in LPG households is μ₂ and the difference is μ = μ₁ - μ₂

The null hypothesis is

H₀: μ ≥ 0 or μ₁ ≥ μ₂

The alternative hypothesis is

Hₐ: μ < 0 or μ₁ < μ₂

Test statistic for 2 sample mean data is given as

Test statistic = (μ₂ - μ₁)/σ

σ = √[(s₂²/n₂) + (s₁²/n₁)]

μ₁ = 3.30

n₁ = 755

s₁ = 1.20

μ₂ = 4.25

n₂ = 750

s₂ = 1.75

σ = √[(1.20²/755) + (1.75²/750)] = 0.07740

z = (3.30 - 4.25) ÷ 0.07740 = -12.27

checking the tables for the p-value of this z-statistic

Significance level = 0.01

The hypothesis test uses a one-tailed condition because we're testing in only one direction.

p-value (for z = -12.27, at 0.01 significance level, with a one tailed condition) = < 0.000000001

The interpretation of p-values is that

When the p-value > significance level, we fail to reject the null hypothesis and when the p-value < significance level, we reject the null hypothesis and accept the alternative hypothesis.

Significance level = 0.01

p-value = 0.000000001

0.000000001 < 0.01

Hence,

p-value < significance level

This means that we reject the null hypothesis, accept the alternative hypothesis & say that true average PEF is lower for children in biomass households than it is for children in LPG households.

C) For FEY for biomass households,

Sample mean = 2.3 L/s

Standard error of the mean = σₓ = (σ/√N)

σ = standard deviation = 0.5

N = sample size = 755

σₓ = (0.5/√755) = 0.0182

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 2.30 ± (1.960 × 0.0182)

CI = 2.30 ± 0.03567

95% CI = (2.264, 2.336)

Simultaneous confidence interval for both = (2.264, 4.375)

This simultaneous interval cannot be the same as that calculated in (a) above because the sample mean obtained for children in biomass households here (using FEY) is much lower than that obtained using PEF in (a).

Hope this Helps!!!

6 0
2 years ago
What is the area of a pentagon with a radius of 3 m? Give the answer to the nearest tenth.
blsea [12.9K]
The area is 21.4 meters
7 0
3 years ago
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