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4 years ago

Find the value of x in each figure. Show work

Mathematics

1 answer:

g100num [7]4 years ago

5 0

Answer:

1. x=28 degrees 2. x=70 degrees

Step-by-step explanation:

QUESTION ONE:

I know that 3x=84, so all I need to do is divide both by 3. I get x=28.

QUESTION TWO:

I can use vertical and complementary angles for this problem. I know that the smaller complementary angle is equal to 160-180, that's 20. Therefore, I get 90=20+x. If I simplify I get 70=x, because 70+20=90.

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Find the product in lowest term 88/66 . 8/13 . 26/7

Sphinxa [80]

Answer:

3 1/21 or 64/21

Step-by-step explanation:

$\frac{88}{66} * \frac{8}{13} * \frac{26}{7}$
$\frac{4}{3}*\frac{8}{13} * \frac{26}{7}$
$\frac{32}{39} * \frac{26}{7}$
$\frac{832}{273}$
$\frac{832}{273} = \frac{64}{21}$
$\frac{64}{21} = 3\frac{1}{21}$

Therefore, the answer is 3 1/21 or 64/21. (They're the same thing.)

3 0

3 years ago

The fraction 3/10 is the difference of 8/10 and which fraction

Mars2501 [29]

Answer:

½ or 11/10

Step-by-step explanation:

3/10 = 8/10 - X

X = 8/10 - 3/10 = 5/10 = 1/2

Or,

X - 8/10 = 3/10

X = 11/10

5 0

3 years ago

Read 2 more answers

The number of states that joined the United States between 1776 and 1849 is twice the number of states that joined between 1850

AlexFokin [52]

Answer: b. 2x = 30

Step-by-step explanation:

Given : 30 states joined the United States between 1776 and 1849

and x states joined between 1850 and 1900 .

If the number of states that joined the United States between 1776 and 1849 is twice the number of states that joined between 1850 and 1900.

i.e. No. of states joined the United States between 1776 and 1849= 2 (No. of states that joined between 1850 and 1900)

i.e . 30= 2(x) [Substitute the values]

i.e . 2x=30

Hence, the true equation : 2x=30

8 0

4 years ago

When my friend tyson died they dictated this song.

SpyIntel [72]

I am sorry for your loss it’s a good song

7 0

3 years ago

Read 2 more answers

How do i solve this differential equation y'=2y-x over 2x-y

Tamiku [17]

$y'=\dfrac{2y-x}{2x-y}$

Let $y=xv$ , where $v=v(x)$ , so that $y'=xv'+v$ . Then the ODE is

$xv'+v=\dfrac{2xv-x}{2x-xv}$
$xv'=\dfrac{2x(v-1)}{x(2-v)}-v$
$xv'=\dfrac{2(v-1)}{2-v}-\dfrac{v(2-v)}{2-v}$
$xv'=\dfrac{v^2-2}{2-v}$

This is separable, so you have

$\dfrac{2-v}{v^2-2}\,\mathrm dv=\dfrac{\mathrm dx}x$

Integrate both sides, solving for $v$ if possible, then replace using $v=\dfrac yx$ and solve for $y$ if possible.

3 0

3 years ago