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miss Akunina [59]
3 years ago
11

In Mr. Romero's auto shop class, the ratio

Mathematics
1 answer:
MrMuchimi3 years ago
5 0

Answer:

boys 5:2 girls

add the ratio parts together

5 + 2 = 7

divide the total number of students by the total number of parts

35/7 = 5

now multiply each part of the ratio by 5

boys 25

girls 10

there are 25 boys

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Vladimir [108]
The answer would be B) 17x-7
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How do you round 23 to the nearest thousand?​
Zielflug [23.3K]

You cannot round 23 to the nearest thousand.

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A pizza dlivery car can travel 11 km for every gallon of gasoline it uses. If the driver's average speed is 28 km/h, how many ho
Svetlanka [38]

Answer:

13.75 hours

Step-by-step explanation:

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2 years ago
Complete the table and show work
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5 0
3 years ago
Read 2 more answers
WHAT IS THE REMAINDER WHEN <img src="https://tex.z-dn.net/?f=32%5E%7B37%5E%7B32%7D%20%7D" id="TexFormula1" title="32^{37^{32} }"
Feliz [49]

Recall Euler's theorem: if \gcd(a,n) = 1, then

a^{\phi(n)} \equiv 1 \pmod n

where \phi is Euler's totient function.

We have \gcd(9,32) = 1 - in fact, \gcd(9,32^k)=1 for any k\in\Bbb N since 9=3^2 and 32=2^5 share no common divisors - as well as \phi(9) = 6.

Now,

37^{32} = (1 + 36)^{32} \\\\ ~~~~~~~~ = 1 + 36c_1 + 36^2c_2 + 36^3c_3+\cdots+36^{32}c_{32} \\\\ ~~~~~~~~ = 1 + 6 \left(6c_1 + 6^3c_2 + 6^5c_3 + \cdots + 6^{63}c_{32}\right) \\\\ \implies 32^{37^{32}} = 32^{1 + 6(\cdots)} =  32\cdot\left(32^{(\cdots)}\right)^6

where the c_i are positive integer coefficients from the binomial expansion. By Euler's theorem,

\left(32^{(\cdots)\right)^6 \equiv 1 \pmod9

so that

32^{37^{32}} \equiv 32\cdot1 \equiv \boxed{5} \pmod9

7 0
2 years ago
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