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amid [387]
3 years ago
14

I would appreciate the help!

Mathematics
2 answers:
pochemuha3 years ago
8 0

Answer:

its b I'm pretty sure. it makes the most sense i

djverab [1.8K]3 years ago
3 0

Answer:

A

Step-by-step explanation:

Multiply 15 by 8 to get 120. 120 + 15 × 11 = 285. 285 + 15 × 22 = 615. 615 + 20 × 7 = 755. 755 + 20 × 6 = 875. 875 + 20 × 14 = 1,155. 1,155 - 292.58 = 862.42. 862.42 - 292.58 = 569.84. Remember PEMDAS.

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A store sells 4 types of chocolate bars and surveyed 50 customers at random
Zanzabum
Hi there! The answer is D. 8%

To find the percentage of the customers who preferred the hazelnut bar we need to know two things:

First we need to know the total amount of customers, which is 50.
Second we need to know how many of these customers preferred the hazelnut bar. This bar is preferred by 4 people.

Now we can fill in the following formula, in order to find our percentage:
\% =  \frac{part}{total}    \times 100 \% =  \frac{4}{50}  \times 100 \% = 0.08 \times 100 \% = 8 \%

Hence, the answer is D. 8%
~ Hope this helps you!
7 0
4 years ago
SOMEONE PLEASE JUST ANSWER ASAP FOR BRAINLIEST!!!
lyudmila [28]
(a-3) × (a+2b)
that the answer
5 0
3 years ago
Read 2 more answers
A circle has diameter endpoints at (7,2) and (p,8), p > 0, and the circle is tangent to the x axis. The circle’s equation can
ycow [4]

Answer:

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Step-by-step explanation:

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3 years ago
I really need help on this
Lesechka [4]

Answer:

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Step-by-step explanation:

4 0
3 years ago
The weight of people in a small town in Missouri is known to be normally distributed with a mean of 186 pounds and a standard de
OleMash [197]

Answer:

the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

Step-by-step explanation:

The summary of the given statistical data set are:

Sample Mean = 186

Standard deviation = 29

Maximum capacity 3,417 pounds or 17 persons.

sample size = 17

population mean =3417

The objective is to determine the probability  that a random sample of 17 persons will exceed the weight limit of 3,417 pounds

In order to do that;

Let assume X to be the random variable that follows the normal distribution;

where;

Mean \mu = 186 × 17 = 3162

Standard deviation = 29* \sqrt{17}

Standard deviation = 119.57

P(X>3417) = P(\dfrac{X - \mu}{\sigma}>\dfrac{X - \mu}{\sigma})

P(X>3417) = P(\dfrac{3417 - \mu}{\sigma}>\dfrac{3417 - 3162}{119.57})

P(X>3417) = P(Z>\dfrac{255}{119.57})

P(X>3417) = P(Z>2.133)

P(X>3417) =1- 0.9834

P(X>3417) =0.0166

Therefore; the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

5 0
3 years ago
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