Answer:
y=Ae^(1.25t)
Step-by-step explanation:
From the expression y=Ae^kt
After two days of the experiment, y = 49 million, t=2
After four days of the experiment, y= 600.25 million, t=4
A is the amount of bacteria present at time zero and t is the time after the experiment (in days)
At t=2 and y =49
49=Ae^2k…………….. (1)
At t=4 and y = 600.25
600.25=Ae^4k………… (2)
Divide equation (2) by equation (1)
600.25/49=(Ae^4k)/(Ae^2k )
12.25=e^2k
Take natural log of both sides
ln(12.25) =2k
2.505 =2k
k=1.25
The exponential equation that models this situation is y=Ae^(1.25t)
Answer:
A. 2x to the power of 3 plus x to the power of 2 plus x plus 1
Step-by-step explanation:
Given Information:
Volume of truck = 15 ft³
Area of base of container = 6 ft²
Required Information:
Height of truck = h = ?
Answer:
Height of truck = h = 2.5 ft
Step-by-step explanation:
The volume of the truck is given by
V = l*w*h
Where l is the length, w is the width, h is the height
The area of the base of container is given by
A = l*w
Where l is the length and w is the width.
Substitute the equation of area into the volume of the truck equation.
V = l*w*h
V = (A)*h
Re-arrange for the height,
h = V/A
h = 15 ft³/6 ft²
h = 2.5 ft
Therefore, the height of the clothing truck is 2.5 ft.
Answer:
Step-by-step explanation:
The last one
I hope I helped you.
Answer: I think it could be anything that it could be anything lower than 96 but I might be wrong, REPEAT, I can be wrong
Step-by-step explanation:
