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Citrus2011 [14]
3 years ago
5

CAN SOMEONE HELP PLEASE!

Mathematics
1 answer:
vlada-n [284]3 years ago
5 0

Answer:

My friend is wrong because a straight angle either consists with two right angles or one obtuse angle and one acute angle.

Step-by-step explanation:

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Find the Area of the triangle, Is it In or In2
mars1129 [50]

Answer:

15 In²

Step-by-step explanation:

Area of triangle = 1/2 × base × height

1/2 × 6 × 5 = 15

8 0
3 years ago
Multiply. Write in simplest form. Help pls!! Tell me the answer no decimals needed just a fraction and simplified!! 2 3/5 x 3 7/
Lady bird [3.3K]

Answer:

10 3/40

Step-by-step explanation: hope i helped

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From the parent function LaTeX: f\left(x\right)=\frac{5}{x}f ( x ) = 5 x, write the equation of the function g(x) if f(x) is tra
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idk

Step-by-step explanation:

5 0
4 years ago
Consider the functions. F(x)=(x+1)2-4 and g(x)=-4|x+1| which statement compares the range of the functions?
Andreyy89

Answer:

<h2>        The fourth</h2>

Step-by-step explanation:

Vertex of f is (-1, -4) so its range is limited to y≥-4

|x+1| is always ≥0 therefore -|x+1| is always ≤0 {4 is insignificant to this - slope doesn't mean in range} so its range is limited to y≤0

3 0
4 years ago
PLEASE HELP ASAP!!!!
Setler [38]

Piecewise Function is like multiple functions with a speific/given domain in one set, or three in one for easier understanding, perhaps.

To evaluate the function, we have to check which value to evalue and which domain is fit or perfect for the three functions.

Since we want to evaluate x = -8 and x = 4. That means x^2 cannot be used because the given domain is less than -8 and 4. For the cube root of x, the domain is given from -8 to 1. That meand we can substitute x = -8 in the cube root function because the cube root contains -8 in domain but can't substitute x = 4 in since it doesn't contain 4 in domain.

Last is the constant function where x ≥ 1. We can substitute x = 4 because it is contained in domain.

Therefore:

\large{  \begin{cases} f( - 8 ) =   \sqrt[3]{ - 8}  \\ f(4) = 3 \end{cases}}

The nth root of a can contain negative number only if n is an odd number.

\large{  \begin{cases} f( - 8 ) =   \sqrt[3]{ - 2 \times -  2 \times   - 2}  \\ f(4) = 3 \end{cases}} \\  \large{  \begin{cases} f( - 8 ) =  - 2\\ f(4) = 3 \end{cases}}

Answer

  • f(-8) = -2
  • f(4) = 3
6 0
3 years ago
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