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weqwewe [10]
3 years ago
10

X^2-18x+209=2x+11 i can't solve it

Mathematics
1 answer:
Viktor [21]3 years ago
6 0

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Blue you sit so pretty west of the one

Sparkle light with yellow icing just a mirror for the sun

Just a mirror for the sun

Just a mirror for the sun

These smiling eyes are just a mirror for...

So much has come before those battles lost and won

This life is shining more forever in the sun

Now let us check our heads and let us check the surf

Staying high and dry's more trouble than it's worth in the sun

Just a mirror for the sun

Just a mirror for the sun

These Smiling eyes are just a mirror for...

In Big Sur we take some time to linger on

We three…

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Math help, will give brainliest and 5 stars :)
Andrew [12]

Answer:

2a) g(x)=3x-6

2b) This is a show kind of answer. The showing of this in the explanation.

2c) I provided the graph.  The lines should be a reflection through the y=x line.  The points (a,b) on y=(1/3)x+2 or swapped to get the points (b,a) on y=3x-6. That is for, example the point (-3,1) is on y=(1/3)x+2 while (1,-3) is on y=3x-6.

Step-by-step explanation:

2a) The inverse of a function is you just swapping x and y around. You also almost always asked to remake y the subject after that though.

So anyways we have this equation y=\frac{1}{3}x+2 to represent that function you have there.

We want to swap x and y:

x=\frac{1}{3}y+2

Now we want to solve for y.

Subtract 2 on both sides:

x-2=\frac{1}{3}y

Multiply both sides by 3:

3(x-2)=y

y=3(x-2)

Distribute:

y=3x-6

So they want us to name the inverse g(x).

g(x)=3x-6

2b) We want to show by composition that these functions are inverses.  That is we want to show f(g(x))=x and g(f(x))=x.

Let's do that:

f(g(x))

Replace g(x) with 3x-6 since g(x)=3x-6.

f(3x-6)

Replace the old input x with the new input (3x-6) in (1/3)x+2.

\frac{1}{3}(3x-6)+2

Distribute:

\frac{3x}{3}-\frac{6}{3}+2

Simplify:

x-2+2

x-0

x.

So we do have f(g(x))=x.

Now to show the other way:

g(f(x))

Replace f(x) with (1/3)x+2 since f(x)=(1/3)x+2.

g((1/3)x+2)

Replace the old input x with the new input (1/3)x+2 in 3x-6.

3((1/3)x+2)-6

Distribute:

3(\frac{1}{3})x+3(2)-6

Simplify:

1x+6-6

x+6-6

x+0

x

So we do have g(f(x))=x.

We have confirmed that f and g are indeed inverses since f(g(x))=x and g(f(x))=x.

2c) Visually if two functions are inverses they should be reflections through the y=x line so that is what we should see since f and g are inverses.

I going to compare both equations to y=mx+b form to determine the y-intercept and the slope.

y=mx+b

y=(1/3)x+2 tells us the slope is 1/3 and the y-intercept is 2.

y=3x-6 tells us the slope is 3 and the y-intercept is -6.

I have color-coded the picture.

5 0
3 years ago
Find the median for the list of numbers
Oliga [24]

Answer:393.8

Step-by-step explanation:

3 0
3 years ago
PLEASE HELP!! Thank you!!!!
SVEN [57.7K]

Answer:

The answer to your question is

Step-by-step explanation:

Data

                   4x - 8y = -16    ------------ (I)

                     x - 2y = - 8     ------------ (II)

a) Solve equation II for x

                     x = 2y - 8

   Substitute x in equation I

                    4(2y - 8) - 8y = -16

                    8y - 32 - 8y = -16

                     8y - 8y = 32 - 16

                            0 = 16             The system has no solution because y was

                                                     cancelled.

b) When a system of equations do not have solution means that the lines are parallels and different.

                                   

6 0
4 years ago
Simplify the following expression (3x^2y)^3
kolezko [41]

Answer:

\large\boxed{\left(3x^2y\right)^3=27x^6y^3}

Step-by-step explanation:

\text{Use}\ (ab)^n=a^nb^n\ \text{and}\ (a^n)^m=a^{nm}\\\\\left(3x^2y\right)^3=3^3(x^2)^3y^3=27x^6y^3

6 0
3 years ago
Suppose lines EF and GH are reflected over the line Y equals X to form the lines JK and LM which statement would be true about t
katrin [286]

Answer:

A) JK and LM will be parallel to each other.

Step-by-step explanation:

On reflection on y=x line the x co-ordinate changes with y co-ordinate and y co-ordinate changes with x co-ordinate

(x,y)\rightarrow (y,x)

Points on line EF

(0,6) , (-5,-2)

On reflection of this line on y=x the new points we get for line JK are

(6,0),(-2,-5)

Points on line GH

(-4,9),(-9,1)

On reflection on y=x line the new points we get for line LM are

(9,-4),(1,-9)

Slope of line JK

m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-5)-0}{(-2)-6} \\m=\frac{-5}{-8}=\frac{5}{8}

Slope of line LM

m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-9)-(-4)}{1-9} \\m=\frac{-9+4}{-8}=\frac{-5}{-8}\\m=\frac{5}{8}

For two line to be parallel, their slopes will be same.

m_{JK} =\frac{5}{8} , m_{LM}=\frac{5}{8}

Since slopes of lines JK and LM are same therefore we can say that these are parallel to each other.

5 0
3 years ago
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