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3 years ago

Help me please of this question

Mathematics

1 answer:

kati45 [8]3 years ago

5 0

Answer:

Step-by-step explanation:

all adds up to 180 degrees

so 4x+3+2x+9=180

=6x+12=180

6x=168

x=28

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One in a thousand people are afflicted with the dreaded zigma disease. A pharmaceutical company develops a test for this disease

Anna [14]

Answer:

Option "A" is correct

Step-by-step explanation:

P(A) probability of event A is true

P(B) probability of event B is true

P(AB) probability of event AB is true

P(BA) probability of event BA is true

P(AB)= (BA) × (A)/(B)

4 0

3 years ago

In 2018, Mike Krzyewski and John Calipari topped the list of highest paid college basketball coaches (Sports Illustrated website

expeople1 [14]

From the data given, we estimate the population mean and population standard deviation. Then, we use this estimate to find a 95% confidence interval for the population variance and the population standard deviation.

Sample:

Salaries in millions of dollars: 2.2, 1.5, 0.5, 1.3, 2.4, 1.5, 2.7, 0.3, 2.0, 0.3

Question a:

The mean is the sum of all values divided by the number of values. So

$\overline{x} = \frac{2.2 + 1.5 + 0.5 + 1.3 + 2.4 + 1.5 + 2.7 + 0.3 + 2.0 + 0.3}{10} = 1.42$

The sample mean salary is of 1.42 million.

Question b:

The standard deviation is the square root of the difference squared between each value and the mean, divided by one less than the number of values.

$s = \sqrt{\frac{(2.2-1.42)^2 + (1.5-1.42)^2 + (0.5-1.42)^2 + (1.3-1.42)^2 + (2.4-1.42)^2 + (1.5-1.42)^2 + (2.7-1.42)^2 + ...}{9}} = 0.8772$

Thus, the estimate for the population standard deviation is of 0.8772 million.

Question c:

The sample size is $n = 10$

The significance level is $\alpha = 1 - 0.05 = 0.95$

The estimate, which is the sample standard deviation, is of $s = 0.8772$ .

Now, we have to find the critical values for the Pearson distribution. They are:

$\chi^2_{\frac{\alpha}{2},n-1} = \chi^2_{0.025,9} = 19.0228$

$\chi^2_{1-\frac{\alpha}{2},n-1} = \chi^2_{0.975,9} = 2.7004$

The confidence interval for the population variance is:

$\frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2},n-1}} < \sigma^2 < \frac{(n-1)s^2}{\chi^2_{1-\frac{\alpha}{2},n-1}}$

$\frac{9*0.8772^2}{19.0228} < \sigma^2 < \frac{9*0.8772^2}{2.7004}$

$0.3641 < \sigma^2 < 2.5646$

Thus, the 95% confidence interval for the population variance is (0.3641, 2.5646)

Question d:

Standard deviation is the square root of variance, so:

$\sqrt{0.3641} = 0.6034$

$\sqrt{2.5646} = 1.6014$

The 95% confidence interval for the population standard deviation is (0.6034, 1.6014).

For more on confidence intervals for population mean/standard deviation, you can check brainly.com/question/13807706

4 0

3 years ago

Determine the amplitude of the following graph.

kodGreya [7K]

Answer:

amplitude = 3

Step-by-step explanation:

the amplitude is the vertical distance from center of the wave to the crest or the trough

5 0

3 years ago

Is the line through points p(-3,-2) and Q(2,3) perpendicular to the line through points R(10,1) and S(15,-6)?

Katen [24]

The slope of line PQ is m1 = ( 3 - (-3) ) / (2 - (-2) ); then m1 = 6/4 = 3/2;
In the same way, the slope of line RS is m2 = -7/5;
But (3/2) x (-7/5) = -21/10, which is diferrent from - 1;
So, the lines aren't perpendicular.

6 0

4 years ago

Aidan uses 1/4 of the water in a bucket to water one potted plant. How many potted plants can aiden water with 3 full buckets of

Ahat [919]

If Aidan can fill 1 potted plant from a full bucket but still have enough left for 3 more, this means Aidan can water 4 plants per full bucket. And if you multiply that 4 by 3 full buckets, it gives you 12, which is the amount of plants 3 full buckets can water.

8 0

4 years ago