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3 years ago

A carpenter makes wooden chairs.

1 answer:

Elena-2011 [213]3 years ago

3 0

He should make 20 dining chairs, and 10 rocking chairs. Making a profit of 2100$

10 rocking chairs x 2hrs = 20hrs

20 dining chairs x 1 = 20hrs

20hrs + 10hrs = 30hrs

90 x 10 = 900$

20 x 60 = 1200$

900 + 1200 = 2100$

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What shapes has parallel sides only

olga2289 [7]

Square, Rectangle and Rhombus

5 0

3 years ago

Write the equation of the line in slope-intercept form that is parallel given the equation and point.

KiRa [710]

Answer:

$y = \frac{4x}{5}+\frac{42}{5}$

Step-by-step explanation:

In order for two lines to be parallel, they must have the same slope. So, we know that the slope of the other line is 4/5.

We're given an ordered pair, so we can solve for $b$ in the (slope-intercept form) equation $y = mx + b$

$2 = \frac{4}{5}(-8) + b\\2 = \frac{-32}{5}+b\\b = 2 + \frac{32}{5}\\ b = \frac{42}{5}$

$y = \frac{4x}{5}+\frac{42}{5}$

4 0

4 years ago

Match the equation with the graph.<br> →<br> Graph E<br> Graph F<br> Graph G<br> Graph H

natka813 [3]

Answer:

Graph E: Y= -1/3x +3

Grpah F: Y= 1/2x

Graph G: Y= x-3

Graph H: Y= -x

Step-by-step explanation:

3 0

3 years ago

1. Find four consecutive even integers such that the sum of the first and third is 6 less than the largest

Sophie [7]

These are indeed quite a lot of exercises, but a lot of them are almost identical - only small computations will change. So, I'm glad to help you with one exercise from every cathegory, but I encourage you to solve the others on your own.

<h2>Exercise 1</h2>

You can call four consecutive integers as

$x,\ x+1,\ x+2,\ x+3$

So, the sum of the first and third is $x+(x+2) = 2x+2$

We want this quantity to be six less than the largest, i.e. $(x+3)-6 = x-3$

So, the equality is

$2x+2 = x-3$

Subtract x from both sides:

$x+2 = -3$

Subtract 2 from both sides:

$x = -5$

So, the consecutive integers are

$-5,\ -4,\ -3,\ -2$

In fact, the sum of the first and third is $-5-3 = -8$ , which is indeed six less than the largest: $-8 = -2-6$

<h2>Exercise 2</h2>

If you call the first odd number $x$ , the next consecutive odd numbers will be $x,\ x+2,\ x+4,\ x+6$

In fact, we have to count skipping two's, because we only want odd integers. From here, you go on like exercise 1: you write the largest (which is x+6), and set it to be two more than the sum of the other three (x, x+2 and x+4)

<h2>Exercise 3</h2>

By the same logic of exercise 2, two consecutive even integers are $x,\ x+2$ , assuming that x is even.

So, you set the equation as usual: the smaller (which is x) is 26 less than three times the larger (which means 3(x+2)-26)

<h2>Exercise 4 to 8</h2>

These are all pretty identical to exercise 1: you start by listing three or four consecutive integers:

$x,\ x+1,\ x+2\quad\text{or}\quad x,\ x+1,\ x+2\ x+3$

and then you translate the request of each exercise accordingly. Remember that expressions like "three times the second number" means that you have to multiply: $3(x+1)$ , while expression like "six more than the first" or "thirteen less than the first" imply adding/subtracting: $x+6$ or $x-13$ .