Usually, this means just going with the flow, not actually doing the work, just look ing like you are. hoped this helped
First one:
cos(A)=AC/AB=3/4.24
cos(B)=BC/AB=3/4.24
Cos(A)/cos(B)=AC/AB / (BC/AB) = AC/AB * AB/BC = AC/BC=3/3=1
Second one:
To solve this problem, we have to ASSUME AFE is a straight line, i.e. angle EFB is 90 degrees. (this is not explicitly given).
If that's the case, AE is a transversal of parallel lines AB and DE.
And Angle A is congruent to angle E (alternate interior angles).
Therefore sin(A)=sin(E)=0.5
This can be done with simple concept of PERMUTATIONS AND COMBINATIONS.
The number can arrange themselves repeatedly to form different numbers. The possible number of ways they can do so is 3×2×1=6
3
×
2
×
1
=
6
ways.
ALTER,
You can arrange these number in 3!
3
!
ways, which finally produces the same result i.e 3!=3×2×1=6
3
!
=
3
×
2
×
1
=
6
ways.