Tell if the ordered pair is a solution of the system of inequalities.

I have no idea what to do

kirill115 [55]

Answer:

Divide.

Step-by-step explanation:

6 0

3 years ago

Look at this graph:

pickupchik [31]

<h3>Answer:</h3>

The Slope is $2$

<h2>Explanation:</h2>

Notice that both the points, $(60,0)$ and $(70,20)$ , are on the line. So we can use those points to calculate the slope. Recall that that slope of the line $m$ can be calculated by $\frac{y_2 -y_1}{x_2 -x_1}\\$ if we have the points, $(x_1,y_1)$ and $(x_2,y_2)$ .

<h3>Calculating for the slope of the line:</h3>

Given:

$(60,0)$

$(70,20)$

$m = \frac{20 -0}{70 -60} \\ m = \frac{20}{10} \\ m = 2$

3 0

3 years ago

Read 2 more answers

D'Naisa mixed her favorite shade of orange paint. She had 111 gallon of orange paint and added 222 quarts of yellow paint and 33

natka813 [3]

Answer:

7.5 Quarts

Step-by-step explanation:

D'Naisa mixed the following:

1 gallon of orange paint
2 quarts of yellow paint
3 pints of red paint.

We are to determine in total, the number of quarts of paint that she mixed. this is done by converting each of the volume to quart.

<u>1 gallon of orange paint</u>

1 gallon = 4 Quarts
Orange Paint=4 Quarts

<u>3 pints of red paint.</u>

1 pint =0.5 quart
3 Pints =3 X 0.5 Quart
=1.5 Quart of red paint

Therefore,

Total Volume of Paint Mixed in quart= Volume of Orange+Yellow+Red

=4+2+1.5

=7.5 Quarts

3 0

2 years ago

Read 2 more answers

1,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000x3422222222222222222222224444444444444444444444443333333335

umka2103 [35]

Answer:100000000000000000000000000000 quint zillion

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Construct the confidence interval for the population mean mu. c = 0.90, x = 16.9, s = 9.0, and n = 45. A 90% confidence inte

Georgia [21]

Answer:

The 90% confidence interval for population mean is $14.7 < \mu < 19.1$

Step-by-step explanation:

From the question we are told that

The sample mean is $\= x = 16.9$

The confidence level is $C = 0.90$

The sample size is $n = 45$

The standard deviation

Now given that the confidence level is 0.90 the level of significance is mathematically evaluated as

$\alpha = 1-0.90$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the standardized normal distribution table. The values is $Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining critical values for $\frac{\alpha }{2}$ instead of that of $\alpha$ is because $\alpha$ represents the area under the normal curve where the confidence level 1 - $\alpha$ (90%) did not cover which include both the left and right tail while $\frac{\alpha }{2}$ is just considering the area of one tail which is what we required calculate the margin of error