The equation 9+12m=6+15(m-1) models the following situation: Movie-rental company A

Mathematics

1 answer:

Marizza181 [45]3 years ago

5 0

Answer:

Start by distributing the 15 to the (m-1). 9+12m=6+15m-15. Then combine like terms. 9+12m=15m-9. Next move the variable all to one side, it doesn't matter which variable you choose. I'll use 12m so when I subtract I am still left with a postive coefficient. To move the 12m we subtract it from both sides of the equation. We are left with 9=3m-9. Next we isolate the m by canceling out the 9. We do this by adding 9 to both sides. We are left with 18=3m. Finally, to completely isolate the m, we must divide both sides by the coefficient, 3. The result is 6=m. The answer is 6 months. You can check this by plugging 6 back into the equation where there is an m. (sorry for the long answer)

Step-by-step explanation:

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the numerator of a fraction x/y is 2 less than the denominator. If 3 is added to both the numerator and denominator, then the su

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Answer:

Step-by-step explanation:

Fraction :x/y

numerator x = y - 2

Now the fraction can be written as: (y-2)/y

3 is added to both denominator and numerator.

After adding 3, the new fraction = $\frac{y-2 +3 }{y + 3 } = \frac{y+ 1 }{y +3}$

The sum of the new fraction and the original fraction is 53/35

$\frac{y+1}{y+3} + \frac{y-2}{y} = \frac{53}{35}\\\\\frac{(y+1)*y}{(y+3)*y}+\frac{(y-2)*(y+3)}{y(y+3)}=\frac{53}{35}\\\\\frac{y^{2}+y}{y^{2}+3y}+\frac{y^{2}+y-6}{y^{2}+3y}=\frac{53}{35}\\\\\frac{y^{2}+y+y^{2}+y-6}{y^{2}+3y}=\frac{53}{35}\\\\\frac{2y^{2} + 2y - 6}{y^{2}+3y}=\frac{53}{35}\\\\$