Answer: 5
Step-by-step explanation:
For how many teachers are both p ∧ r true and q false?
(p ∧ r) ∧ (q')
q' = q complement (not in q)
p intersection r = (p ∧ r) = 9
both p ∧ r true and q false = (8+6) - 9
both p ∧ r true and q false = 14 - 9 = 5
OR
p + r - p ∧ r
8 + 6 - 9 = 14 - 9 = 5
The solution is 2sqrt77/77. You just fill in 2/3 for the x's. When you do that, you do that you get (2/3)/sqrt(9-[2/3]^2) which, simplified, is (2/3)/sqrt(9-[4/9]). Now use the common denominator under the radical of 9 to get (2/3)/sqrt([81-4]\9). Simplifying even further gives you (2/3)/([sqrt(77)]/3). Now do that division by multiplying 2/3 by the reciprocal of ([sqrt(77)]/3) to get 2/sqrt77. I rationalized the denominator to get that result up there.
Answer:
Step-by-step explanation:
3(x + 4) - 5 = 2x + 4
solve for x
x = -3
Answer:
D because y increases by 0 each time while x increases by 2 each time
