4 years ago

Helpppppp me plssssss

Mathematics

1 answer:

MaRussiya [10]4 years ago

8 0

I have solved the answer in the pic below, hope it helpss!!!!

You might be interested in

The scale on a map is 1 inch= 2.5 miles. Two towns on the map are 6 inches apart. What is the actual distance between the towns

mixas84 [53]

Answer:

The answer is 180.

Just multiply thirty and six.

Hope that helps!

8 0

3 years ago

Read 2 more answers

A total of 450 theater tickets were sold. Student tickets cost $3 and adult tickets cost $5. If the total receipts were $2000, h

MatroZZZ [7]

Answer:

i have made it in above picture hope it helps

8 0

3 years ago

The amount of money an electrician charges when visiting a home to make a repair is shown by the linear equation c = 120 + 65h,

OleMash [197]

Just add
120+65(2.5)
=120+162.5
=282.5

7 0

4 years ago

Osmond has £6 he buys some cans of drink at 85p each and has 5p leftover how many cans of drinks did he buy

worty [1.4K]

Answer:

7 cans

Step-by-step explanation:

<u>Given</u>

Cost of drink = 85p
Money given = £6
Money left = 5p

<u>Solution</u>

£6 = 600 p
85x + 5 = 600
85x = 595
x = 595/85
x = 7

8 0

4 years ago

Diagonalize a if possible. (find p and d such that a = pdp−1 for the given matrix

podryga [215]

$\mathbf A=\begin{bmatrix}-10&30\\-6&17\end{bmatrix}$

Compute the eigenvalues of $\mathbf A$ :

$\begin{vmatrix}-10-\lambda&30\\-6&17-\lambda\end{vmatrix}=(-10-\lambda)(17-\lambda)+180=(\lambda-5)(\lambda-2)=0$

$\implies\lambda=5,\lambda=2$

Find the corresponding eigenvectors $\eta$ :

$\lambda_1=2\implies\begin{bmatrix}-12&30\\-6&15\end{bmatrix}\eta_1=\mathbf0$

$\implies\eta_1=\begin{bmatrix}5\\2\end{bmatrix}$

$\lambda_2=5\implies\begin{bmatrix}-15&30\\-6&12\end{bmatrix}\eta_2=\mathbf0$

$\implies\eta_2=\begin{bmatrix}2\\1\end{bmatrix}$

Now,

$\mathbf A=\begin{bmatrix}\eta_1&\eta_2\end{bmatrix}\mathrm{diag}(\lambda_1,\lambda_2)\begin{bmatrix}\eta_1&\eta_2\end{bmatrix}^{-1}$

$\mathbf A=\begin{bmatrix}5&2\\2&1\end{bmatrix}\begin{bmatrix}2&0\\0&5\end{bmatrix}\begin{bmatrix}5&2\\2&1\end{bmatrix}^{-1}$

6 0

3 years ago