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Lunna [17]
4 years ago
9

Helpppppp me plssssss

Mathematics
1 answer:
MaRussiya [10]4 years ago
8 0

I have solved the answer in the pic below, hope it helpss!!!!

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The scale on a map is 1 inch= 2.5 miles. Two towns on the map are 6 inches apart. What is the actual distance between the towns
mixas84 [53]

Answer:

The answer is 180.

Just multiply thirty and six.

Hope that helps!

8 0
3 years ago
Read 2 more answers
A total of 450 theater tickets were sold. Student tickets cost $3 and adult tickets cost $5. If the total receipts were $2000, h
MatroZZZ [7]

Answer:

i have made it in above picture hope it helps

8 0
3 years ago
The amount of money an electrician charges when visiting a home to make a repair is shown by the linear equation c = 120 + 65h,
OleMash [197]
Just add 
120+65(2.5)
=120+162.5
=282.5
7 0
4 years ago
Osmond has £6 he buys some cans of drink at 85p each and has 5p leftover how many cans of drinks did he buy
worty [1.4K]

Answer:

  • 7 cans

Step-by-step explanation:

<u>Given</u>

  • Cost of drink = 85p
  • Money given = £6
  • Money left = 5p

<u>Solution</u>

  • £6 = 600 p
  • 85x + 5 = 600
  • 85x = 595
  • x = 595/85
  • x = 7
8 0
4 years ago
Diagonalize a if possible. (find p and d such that a = pdp−1 for the given matrix
podryga [215]

\mathbf A=\begin{bmatrix}-10&30\\-6&17\end{bmatrix}


Compute the eigenvalues of \mathbf A:


\begin{vmatrix}-10-\lambda&30\\-6&17-\lambda\end{vmatrix}=(-10-\lambda)(17-\lambda)+180=(\lambda-5)(\lambda-2)=0

\implies\lambda=5,\lambda=2


Find the corresponding eigenvectors \eta:


\lambda_1=2\implies\begin{bmatrix}-12&30\\-6&15\end{bmatrix}\eta_1=\mathbf0

\implies\eta_1=\begin{bmatrix}5\\2\end{bmatrix}


\lambda_2=5\implies\begin{bmatrix}-15&30\\-6&12\end{bmatrix}\eta_2=\mathbf0

\implies\eta_2=\begin{bmatrix}2\\1\end{bmatrix}


Now,


\mathbf A=\begin{bmatrix}\eta_1&\eta_2\end{bmatrix}\mathrm{diag}(\lambda_1,\lambda_2)\begin{bmatrix}\eta_1&\eta_2\end{bmatrix}^{-1}

\mathbf A=\begin{bmatrix}5&2\\2&1\end{bmatrix}\begin{bmatrix}2&0\\0&5\end{bmatrix}\begin{bmatrix}5&2\\2&1\end{bmatrix}^{-1}

6 0
3 years ago
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