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Diano4ka-milaya [45]
2 years ago
11

Factorise 2xsquared X 7x +3

Mathematics
1 answer:
Monica [59]2 years ago
5 0

Answer:

 (-2x - 1) • (x + 3)

Step-by-step explanation:

3.2     Factoring  2x2 + 7x + 3

The first term is,  2x2  its coefficient is  2 .

The middle term is,  +7x  its coefficient is  7 .

The last term, "the constant", is  +3

Step-1 : Multiply the coefficient of the first term by the constant   2 • 3 = 6

Step-2 : Find two factors of  6  whose sum equals the coefficient of the middle term, which is   7 .

     -6    +    -1    =    -7

     -3    +    -2    =    -5

     -2    +    -3    =    -5

     -1    +    -6    =    -7

     1    +    6    =    7    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  1  and  6

                    2x2 + 1x + 6x + 3

Step-4 : Add up the first 2 terms, pulling out like factors :

                   x • (2x+1)

             Add up the last 2 terms, pulling out common factors :

                   3 • (2x+1)

Step-5 : Add up the four terms of step 4 :

                   (x+3)  •  (2x+1)

            Which is the desired factorization

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{c(1) = 3/16<br> {c(n)=c(n−1)⋅4<br> ​ <br><br> what is the 3rd term in this sequence?
mote1985 [20]

Answer:

\large\boxed{c(3)=3}

Step-by-step explanation:

\left\{\begin{array}{ccc}c(1)=\dfrac{3}{16}\\\\c(n)=c(n-1)\cdot 4\end{array}\right

Put n = 2 and next n = 3 to the recursive formula:

c(2)=c(2-1)\cdot4=c(1)\cdot4\to c(2)=\dfrac{3}{16}\cdot4=\dfrac{3}{4}\\\\c(3)=c(3-1)\cdot4=c(2)\cdot4\to c(3)=\dfrac{3}{4}\cdot4=3

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3 years ago
every prime number greater than 10 has a digit in the ones place that is included in which set of numbers below?
stich3 [128]
So we can start with the full of possibilities and eliminate them one by one.

The full set is {0,1,2,3,4,5,6,7,8,9}.

Now we know that any prime greater than 2 is odd as otherwise it would have 2 as a factor, so we can eliminate all of these digits that would be an even number, leaving:

{1,3,5,7,9}

We also know that any prime greater than 5 cannot be a multiple of 5 and that all numbers with 5 in the digits are a multiple of 5, so we can eliminate 5.

{1,3,7,9}

We know that 11,13,17 and 19 are all primes, so we cannot eliminate any more of these, leaving the set:

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2 years ago
What is the equation of the line that passes through the point (-6, -8) and has a slope of 1/3
ivanzaharov [21]

Answer <u>(assuming it can be in point-slope form)</u>:

y + 8 = \frac{1}{3} (x+6)

Step-by-step explanation:

With the given information, we can use the point-slope formula, y-y_1 = m (x-x_1), to write the equation of the line. Substitute values for the m , x_1, and y_1 in the formula to do so.

The m represents the slope, so substitute \frac{1}{3} in its place. The x_1 and y_1 represent the x and y values of one point the line intersects, so substitute -6 for x_1 and -8 for y_1. This gives the following answer and equation (just make sure to convert the double negatives into positives:  

y-(-8) = \frac{1}{3} (x-(-6))\\y + 8 = \frac{1}{3} (x+6)

3 0
2 years ago
Read 2 more answers
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