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3 years ago

NEED HELP ASAP PLEASE!!!

Mathematics

1 answer:

maks197457 [2]3 years ago

5 0

Answer:

its seven

Step-by-step explanation:

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In a In a school of 567 pupils 278 are boys.

DIA [1.3K]

Answer:

49% of the pupils are boys and 51% are girls.

Step-by-step explanation:

Alright, so first, you've got to find the total number of students: 567.

Now, to find the value of 1%, you divide 567 by 100, which will give you 5.67.

Next, you divide the number of male students by the value of 1%. That's 278 ÷ 5.67 = 49.0299823633157.

Subtracting that from 100% gives you 50.9700176366843 (percentage of girls)

Now, you can't write all that down, so you'll round it! 49.0299823633157 will round down, because 0 is less than 5, so it's 49%. 50.9700176366843 rounds up, because 9 is greater than 5, so that's 51%.

Therefore, 49% of the pupils are boys and 51% are girls.

I hope this helps!

4 0

3 years ago

Express the quotient in simplest form.

HACTEHA [7]

Answer:

c. $\frac{(x - 2)}{x^{3}}$

Step-by-step explanation:

$\frac{(x - 2)(x + 2)}{x^{2}(x + 7)}$ × $\frac{(x + 7)(x - 3)}{ x(x - 3)(x + 2)}$

$\frac{(x - 2)}{x^{3}}$

8 0

3 years ago

State if the triangles are similar. If so, how do you know they are

DIA [1.3K]

Step-by-step explanation:

they're similar since 36 % 9 = 0 and 24 % 6 = 0 (they leave no remainder)

6 0

2 years ago

Someone please help !!!!

AnnZ [28]

It is A. when you synthetic divide you end up underneath 2 7 0. the 0 is the remainder. the other makes 2x+7

6 0

3 years ago

Read 2 more answers

Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi

katrin2010 [14]

Answer:

Test scores of 10.2 or lower are significantly low.

Test scores of 31.4 or higher are significantly high.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 20.8, \sigma = 5.3$