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tino4ka555 [31]
3 years ago
9

Nanda Yueh and Lane Zuriff sell homes for ERA Realty. Over the past 6 months they sold 136 homes. Nanda sold 3 times as many hom

es as Lane. How many homes did each sell? Lane Nanda homes homes​
Mathematics
1 answer:
Marta_Voda [28]3 years ago
5 0

Answer:

Lane sold 34 homes.

Nanda sold 102 homes.

Step-by-step explanation:

This question can be solved by a system of equations.

I am going to say that:

Nanda sold x homes

Lane sold y homes

Over the past 6 months they sold 136 homes.

This means that x + y = 136

Nanda sold 3 times as many homes as Lane.

This means that x = 3y

Replacing in the first equation:

x + y = 136

3y + y = 136

4y = 136

y = \frac{136}{4} = 34

Lane sold 34 homes.

x = 3y = 34*3 = 102

Nanda sold 102 homes.

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(24*32)/(2*3)
(768)/(6)
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3 years ago
Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
3 years ago
The perimeter of a rectangular field is 84 yards. The ratio of the length to the width is 2:1. What are the length, width and ar
Ivenika [448]

Given:

  • the perimeter of a rectangular field is 84 yards
  • the ratio of the length to the width is 2:1

To find:

  • the length
  • the width
  • the area

Answer:

Let's assume that the length is 2x and the width is 1x.

We know that the formula to find the perimeter of a rectangle is as follows:

Perimeter = 2 × (Length + Width)

Substituting the values that we have, into the formula above,

84 = 2 × (2x + 1x)

84 = 2 × 3x

84/2 = 3x

42 = 3x

x = 42/3

x = 14

Since we know the value of 'x', let's use it to find the length and the width.

Length = 2x = 2 × 14 = 28

Width = 1x = 1 × 14 = 14

Since we now know the length and the width, let's find the area of the rectangle.

The formula to find the area of a rectangle:

Area = Length × Width

Substituting the values we have into the formula,

Area = 28 × 14

Area = 392

Therefore, the area of the rectangle is 392 square yards.

Hope it helps. :)

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Answer:

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Step-by-step explanation:

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Answer: The value of x is 7

Step-by-step explanation:

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