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Delvig [45]
3 years ago
8

I need help please ten points for question number three !!!!!!!!.......!!!!!!.....

Mathematics
2 answers:
astraxan [27]3 years ago
5 0

Answer:

what

Step-by-step explanation:

LenKa [72]3 years ago
4 0

Answer:

where is the question though

Step-by-step explanation:

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A grain silo is composed of a cylinder and a hemisphere.
viktelen [127]

Answer:  The approximate total volume of the silo is  116.5 m3

Step-by-step explanation:

Hi, the volume of the silo is equal to: volume of the cylinder + volume of the hemisphere:

Volume of the cylinder:

V = π x r²x h

Where:

R = radius (in this case, to obtain the radius we have to divide the diameter by two since radius = diameter /2)

h = height

Replacing with the values given:

V = π x r²x h = 3.14 x (4.4/2) ²6.2= 3.14 x (2.2)²x 6.2 = 94.22512 m3

And for the hemisphere:

Volume of the hemisphere: 2/3 x π x r3

Replacing with the values given;

v= 2/3 x 3.14 x 2.2∧3= 22.28m3

Finally, adding both results:

Volume of the silo = volume of the cylinder + volume of the hemisphere:

94.22 m3+ 22.28m3 = 116.5 m3

7 0
3 years ago
Estimate the product. Then find the actual product.
Artist 52 [7]

Answer:

it  is in the steps 4443.6 actual product

estimate is 4444

Step-by-step explanation:

483*9.2=4443.6 actual product

6 0
3 years ago
Read 2 more answers
An author is having a book signing at a store. He agrees to give 5% of his profit to literacy programs and 15% of his profit to
Monica [59]
He took home $160 after donating 20% (which is $40)


4 0
3 years ago
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Find the probability of being dealt a full house. (Round your answer to six decimal places.)?
vesna_86 [32]

I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.

A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.

Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.

The number of ways of drawing 2 aces and 3 2s is

\dbinom42\dbinom43=24

and the number of ways of drawing 3 aces and 2 2s is the same,

\dbinom43\dbinom42=24

so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.

Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is

2\dbinom{13}2\dbinom42\dbinom43=3744

The total number of hands that can be drawn is

\dbinom{52}5=2,598,960

Then the probability of getting a full house is

\dfrac{2\binom{13}2\binom42\binom43}{\binom{52}5}=\dfrac6{4165}\approx\boxed{0.001441}

4 0
3 years ago
I need help with algebra
Ivenika [448]

Answer:

A and can I have brainliest

Step-by-step explanation:

6 0
3 years ago
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