I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
right?
In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this:
(y² + 1)(y - 9) = 0
Now separate your two parentheses to two separate problems:
(y² + 1) = 0 and (y - 9) = 0
Now you're y² + 1 will equal:
y² = -1
y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part.
Now solve y - 9 = 0:
y = 9 <-- Since we added nine to both sides to get this.
So you're final answer should be y = i and 9
when you simplify this you get 1/16x^8
S(t) = S0·(1 + rate)t<span>S(t) = salary at year t
<span>S0 = starting salary = $35,000
</span>rate = 4% = 0.04
<span>t = years</span></span>
Answer:
B is the solution
Step-by-step explanation:
-6.53 is the furthest from 0
-6 1/4 is closer to 0
6.57 is positive and more than 0
6 3/4 is also positive and more than 6.57
Answer:
5/10 20/28
Step-by-step explanation:
i think only these.. hope this helps..
