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Studentka2010 [4]
3 years ago
13

Write an equation for the proportional relationship shown in the table.

Mathematics
1 answer:
VladimirAG [237]3 years ago
3 0

9514 1404 393

Answer:

  y = 38x

Step-by-step explanation:

The constant of proportionality (k) is the value of y when x=1. The table shows that to be 38. Then the equation is ...

  y = kx

  y = 38x

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HELP!!!<br> what is x?<br> x2/4*=50
Gnoma [55]
Hello there. 

THe answer is x=100.

Plz branliest
5 0
3 years ago
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What is the coefficient of abc when the product (a + 2b)(b + 2c)(c + 2a) is expanded and
oksian1 [2.3K]

Answer:

The coefficient is 9

Step-by-step explanation:

(a)(b)(c)+(a)(2c)(2a)+(2b)(b)(c)+(2b)(2c)(2a)

abc+4ca^2+2cb^2+8abc

9abc+4ca^2+2cb^2

8 0
3 years ago
Factor completely, then place the answer in the proper location on the grid. <br> 6х^2 - 3х - 30
Tems11 [23]

Answer:

3(x + 2)(2x - 5)

Step-by-step explanation:

Given

6x² - 3x - 30 ← factor out 3 from each term

= 3(2x² - x - 10) ← factor the quadratic

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 2 × - 10 = - 20 and sum = - 1

The factors are + 4 and - 5

Use these factors to split the x- term

2x² + 4x - 5x - 10 ( factor the first/second and third/fourth terms )

= 2x(x + 2) - 5(x + 2) ← factor out (x + 2) from each term

= (x + 2)(2x - 5), thus

2x² - x - 10 = (x + 2)(2x - 5) and

6x² - 3x - 30

= 3(x + 2)(2x - 5) ← in factored form

7 0
3 years ago
Solve this equation for x: 2x^2 + 12x - 7 = 0
zhannawk [14.2K]

Answer:

x=0.5355 or x=-6.5355

First step is to: Isolate the constant term by adding 7 to both sides

Step-by-step explanation:

We want to solve this equation: 2x^2 + 12x - 7 = 0

On observation, the trinomial is not factorizable so we use the Completing the square method.

Step 1: Isolate the constant term by adding 7 to both sides

2x^2 + 12x - 7+7 = 0+7\\2x^2 + 12x=7

Step 2: Divide the equation all through by the coefficient of x^2 which is 2.

x^2 + 6x=\frac{7}{2}

Step 3: Divide the coefficient of x by 2, square it and add it to both sides.

Coefficient of x=6

Divided by 2=3

Square of 3=3^2

Therefore, we have:

x^2 + 6x+3^2=\frac{7}{2}+3^2

Step 4: Write the Left Hand side in the form (x+k)^2

(x+3)^2=\frac{7}{2}+3^2\\(x+3)^2=12.5\\

Step 5: Take the square root of both sides and solve for x

x+3=\pm\sqrt{12.5}\\x=-3\pm \sqrt{12.5}\\x=-3+ \sqrt{12.5}, $ or $x= -3- \sqrt{12.5}\\$x=0.5355 or x=-6.5355

6 0
3 years ago
If x2 + y2 = 14 and xy = 5, find the value of (1/2 x + 1/2 y)2.
aleksley [76]

Answer:

(½x+½y)²=6

Step-by-step explanation:

x^2 + y^2 = 14, xy=5

(A+B)^2=A^2 +2AB+B^2... (*)

(1/2x+1/2y)^2 =(*)

(1/2x)^2 +2(1/2x)(1/2y)+(1/2y)^2 =

1/4x^2 +1/2xy+1/4y^2=

1/4(x^2 +y^2) +1/2(xy)=

1/4*14+1/2*5=

14/4+5/2=

14/4+10/4=

24/4=6

let me know if I'm wrong.

5 0
3 years ago
Read 2 more answers
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