D. haploid cells with a smaller number of chromosomes than the parent cells.
Blood reticulocyte counts provide information regarding rate of erythrocyte formation.
Hi! :)
Make a = q, aa (homozygous recessive) = q^2,
A = p, AA (homozygous dominant) = p^2, and
2pq = heterozygous
This was derived from p + q = 1
Therefore all a in pop (q) = 20% = .20
And all A in pop (p) = 80% = .80
Since the disease is homozygous recessive (affected), then aa = qq or q×q = q^2
q^2 = (.20)^2 = .040 = 4%
Answer: 4%