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3 years ago

How many solutions does the equation 22 = 81 have?

Mathematics

1 answer:

agasfer [191]3 years ago

7 0

Answer:

No solutions.

Step-by-step explanation:

22 does not equal 81, so therefore no solutions.

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A farmer knows that a grocery store will reject a shipment of his vegetables if more than 4% of the vegetables contain blemishes

kykrilka [37]

Answer:

Assumption A is violated

Step-by-step explanation:

x = number of blemishes = 8

n = sample size = 150

proportion = x/n = 8/150 = 0.0533

1. large counts: np> 10

= 150 * 0.0533 >10

= 7.995 > 10

this assumpton is obviously violated. 7.995 is not greater than 10

2. Large Counts: n(1 - p) > 10

150(1-0.0533)>10

150-7.995 > 10

142.005> 10

there is no violation. The assumption is satisfied

3. This assumption is satisfied. this is because the tomatoes were selected using simple random sampling.

4. 10% of the population = 0.1 * 2000 = 200

the sample size = 150

150 < 200

this assumption is satisfied

3 0

3 years ago

What are the answers

nikdorinn [45]

Answer:

Entschuldigung, ich weiß die Antwort nicht

4 0

3 years ago

The occupancy of the room must be less than 437 people

ale4655 [162]

It would be p < 437.

5 0

3 years ago

What is 20 over 24 in a percent

Gala2k [10]

$\frac{20}{24}
$

If you want to find the answer just divide the 20 by the 24, then multiply by 100 to get your percentage.

20 ÷ 24 = 0.83

0.83 × 100 = 83%

↑ ↑ ↑ Hope this helps! :D

7 0

3 years ago

If you invest $100,000 in an account earning 8% interest compounded annually, how long will it take until the account holds $300

Monica [59]

We have been given that you invest $100,000 in an account earning 8% interest compounded annually. We are asked to find the time it will take the amount to reach $300,000.

We will use compound interest formula to solve our given problem.

$A=P(1+\frac{r}{n})^{nt}$ , where,

A = Final amount after t years,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

$8\%=\frac{8}{100}=0.08$

$300,000=100,000(1+\frac{0.08}{1})^{1\cdot t}$

$300,000=100,000(1.08)^{t}$

$\frac{300,000}{100,000}=\frac{100,000(1.08)^{t}}{100,000}$

$3=(1.08)^{t}$

$(1.08)^{t}=3$

Let us take natural log on both sides of equation.

$\text{ln}((1.08)^{t})=\text{ln}(3)$

Using natural log property $\text{ln}(a^b)=b\cdot \text{ln}(a)$ , we will get:

$t\cdot \text{ln}(1.08)=\text{ln}(3)$

$\frac{t\cdot \text{ln}(1.08)}{\text{ln}(1.08)}=\frac{\text{ln}(3)}{\text{ln}(1.08)}$

$t=\frac{1.0986122886681097}{0.0769610411361283}$

$t=14.274914586$

Upon rounding to nearest tenth of year, we will get:

$t\approx 14.3$

Therefore, it will take approximately 14.3 years until the account holds $300,000.

7 0

3 years ago