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ioda
2 years ago
7

Evaluate the expression x+4x-3+3x^2-2x when x = 5

Mathematics
1 answer:
Setler79 [48]2 years ago
5 0

Given:

The expression is

x+4x-3+3x^2-2x

To find:

The value of given expression when x=5.

Solution:

We have,

x+4x-3+3x^2-2x

Substituting x=5 in the above expression, we get

=(5)+4(5)-3+3(5)^2-2(5)

=5+20-3+3(25)-10

=5+20-3+75-10

On further simplification, we get

=(5+20+75)+(-3-10)

=100+(-13)

=100-13

=87

Therefore, values of the given expression at x=5 is 87.

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Answer:

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Step-by-step explanation:

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A 26-foot ladder is placed against a house and reaches the 24-foot roof. What is the distance between the base of the ladder and
hammer [34]

Answer:

The distance from the base of the ladder to the base of the house is 10ft

Step-by-step explanation:

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