(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
Answer:
-7.5
Step-by-step explanation:
Simplify
-4b - 5 + 2b = 10
-2b - 5 = 10
-2b = 15
b = -7.5
Its very simple. You see, consider a right angled triangle, and the side opposite to the right angle or the largest side is Hypotnuse and the side the is adjacent to the angle that you choose is the adjacent side.
Answer:
The percent of the people who tested positive actually have the disease is 38.64%.
Step-by-step explanation:
Denote the events as follows:
<em>X</em> = a person has the disease
<em>P</em> = the test result is positive
<em>N</em> = the test result is negative
Given:
Compute the value of P (P|X) as follows:
Compute the probability of a positive test result as follows:
Compute the probability of a person having the disease given that he/she was tested positive as follows:
The percentage of people having the disease given that he/she was tested positive is, 0.3864 × 100 = 38.64%.
The simplification for this equation would be, 4x^2 y^26
