<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%7Bx%20%5C%3A%7D%20" id="TexFormula1" title="f(x) = \sqrt{x \:} "

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3 years ago

alt="f(x) = \sqrt{x \:} " align="absmiddle" class="latex-formula">
$g(x) = \frac{x - 5}{2x + 1}$
what is the domain and range of fg.

Mathematics

1 answer:

cluponka [151]3 years ago

3 0

(-∞, -1/2) not for sure if that’s right

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The distance d (in feet) that it

Marta_Voda [28]

Answer:

40 mph

Step-by-step explanation:

To find the maximum speed at which the car can travel, as the distance it requires to stop is 168 feet, we just need to use the value of d = 168 in the equation, and then find the value of s:

168 = 0.05s^2 + 2.2s

0.05s^2 + 2.2s - 168 = 0

Using Bhaskara's formula: we have:

Delta = 2.2^2 + 4*0.05*168 = 38.44

sqrt(Delta) = 6.2

s1 = (-2.2 + 6.2)/0.1 = 40 mph

s2 = (-2.2 - 6.2)/0.1 = -84 mph (a negative value does not make sense as 's' is the speed of the car)

So the maximum speed of the car is 40 mph

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4 years ago

Questions attached below

Cerrena [4.2K]

Step-by-step explanation:

1 ) 1/2×4×8

=16

2) 1/2 ×7×6

=21

3)1/2×14×36

=252

4)1/2×25×54

675

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3 years ago

The number of surface flaws in a plastic roll used for auto interiors follows a Poisson distribution with a mean of 0.05 flaw pe

ElenaW [278]

Answer:

0.6065

Step-by-step explanation:

Probability mass function of probability distribution : $P(X=x)=\frac{e^{-\lambda} \times \lambda^x}{x !}$

a mean of 0.05 flaw per square foot

Each car contains 10 sq.feet of the plastic roll

Mean = 0.05

Mean = $\lambda = 0.05 \times 10=0.5$

We are supposed to find What is the probability that there are no flaws in a given car’s interior i.e,P(X=0)

Substitute the value in the formula

$P(X=0)=\frac{e^{-0.5} \times (0.5)^0x}{0 !}$

$P(X=0)=\frac{e^{-0.5} \times (0.5)^0}{1}$

$P(X=0)=0.6065$

Hence the probability that there are no flaws in a given car’s interior is 0.6065

5 0

3 years ago

1.0835 rounded to the nearest tenth

Aloiza [94]

Answer:

1.1

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A train leaves Philadelphia at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train t

polet [3.4K]

Answer: First train speed shall be 42 mi/hr

Second train speed shall be 84 mi/hr

Yes it is the valid answer, it gets annoying when almost everyone enters the wrong answer for a good laugh. Either way, hope this helps! Have a spectacular day.

Step-by-step explanation:

What is the 1st train's head start in miles?

Let +s+ = the speed of the 1st train in mi/hr

From 2PM to 4PM is 2 hrs

+d%5B1%5D+=+s%2A2+

---------------------

Let +d+ = distance the 2nd train travels until

it overtakes the 1st train

From 4PM to 6PM is 2 hrs

Start time when the 2nd train leaves

---------------------

Equation for 1st train:

(1) +d+-+2s+=+s%2A2+

Equation for 2nd train:

(2) +d+=+%28+s%2B42+%29%2A2+

--------------------

Substitute (2) into (1)

(1) +%28+s%2B42+%29%2A2+-+2s+=+s%2A2+

(1) +2s+%2B+84+-+2s+=+2s+

(1) +2s+=+84+

(1) +s+=+42+

and

+s%2B+42+=+42+%2B+42+

+s+%2B+42+=+84+

------------------

The 1st train's speed is 42 mi/hr

The 2nd train's speed is 84 mi/hr

---------------------------

check:

(2) +d+=+%28+s%2B42+%29%2A2+

(2) +d+=84%2A2+

(2) +d+=+168+

and

(1) +d+-+2s+=+s%2A2+

(1) +d+-+2%2A42+=+42%2A2+

(1) +d+=+84+%2B+84+

(1) +d+=+168+

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3 years ago