What is the solution of 5y + 2 = 42?

Two numbers are the ratio of 2:7. their sum is 63. what is the larger number?

MariettaO [177]

Answer:

49

Step-by-step explanation:

step 1: Add the ratios 2:7 which is 2+7=9

step 2: divide the bigger ratio (7) by the total calculated in step 1 (9) and multiply by the total number given (63)....

step 3: we have 7/9×63 which is 49

therefore the bigger number is 49

8 0

2 years ago

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The number of purses a vendor sells daily has the probability distribution represented in the table. Number of Purses, x 0 1 2 3

Arada [10]

Answer:

(D)$81

Step-by-step explanation:

Given that the number of purses a vendor sells daily has the probability distribution represented in the table.

Expected Value, $E(x)=\sum_{i=1}^{n}x\cdot p(x)$

Therefore:

$E(x)=(0X0.35)+(1X0.15)+(2X0.2)+(3X0.2)+(4X0.03)+(5X0.07)\\=0+0.15+0.4+0.6+0.12+0.35\\E(x)=1.62$

If each purse sells for $50.00, the number of expected daily total dollar amount taken in by the vendor from the sale of purses

=Expected Value X $50

=1.62 X $50

=$81

The correct option is D.

6 0

3 years ago

A baseball player throws a ball from second base to home plate. How far does the player throw the ball?

Fynjy0 [20]

Answer:

The player throws 127.3 ft from second base to home plate.

Step-by-step explanation:

Given:

Distance from home to first base = 90 ft

Distance from first base to second base = 90 ft

We need to find the distance from second base to home.

Solution:

Now we can assume the complete scenario to be formed as a right angled triangle with two sides given and to find the third side.

Now by using Pythagoras theorem which states that;

Square of the hypotenuse side is equal to sum of squares of other two sides.

framing in equation form we get;

distance from second base to home = $\sqrt{90^2+90^2}= 127.27 \ ft$

Rounding to nearest tent we get;

distance from second base to home = 127.3 ft

Hence The player throws 127.3 ft from second base to home plate.

6 0

3 years ago

I am making this question for emmatannerfns to chat with me

Arturiano [62]

Answer:

Hi , how are you ig .

Step-by-step explanation:

8 0

3 years ago

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According to a study done by Nick Wilson of Otago University Wellington, the probability a randomly selected individual will not

Lorico [155]

Answer and Step-by-step explanation:

From the question statement we get know that it is Binomial distribution because there are only two possible outcomes so we need to use Binomial Probability Distribution for this question.

Formula for the Binomial Probability Distribution:

P(X)= p^x q^(n-x)

Where,

C_x^n=n!/(n-x)!x! (i.e. combination)
x= total number of successes
p=probability of success (p=1-q)
q=probability of failure (q=1-p)
n=number of trials
P(X)= probability of total number of successes

Answer and explanation for each part of the question are as follow:

a.What is the probability that among 10 randomly observed individuals exactly 4 do not cover their mouth when sneezing?

Solution:

Given that

n=10

p=0.267 (because p is the probability of success which is “number of individuals not covering their mouths when sneezing” in the question)

q=1-0.267=0.733

x=4 (number of successes i.e. individuals not covering their mouths)

C_x^n=n!/(n-x)!x!=10!/(10-4)!4!=210

P(X)=C_x^n p^x q^(n-x)=210×〖(0.267)〗^4×〖0.733〗^(10-4)

P(X)=210×0.00508×0.155

P(X)=0.165465

b. What is the probability that among 10 randomly observed individuals fewer than 3 do not cover their mouth when sneezing?

Solution:

Given that

n=10

p=0.267 (because p is the probability of success which is “number of individuals not covering their mouths when sneezing” in the question)

q=1-0.267=0.733

x=3 (number of successes i.e. individuals not covering their mouths)

C_x^n=n!/(n-x)!x!=10!/(10-3)!3!=120

P(X)=C_x^n p^x q^(n-x)=120×(0.267)^3×〖0.733〗^(10-3)

P(X)=120×0.01903×0.1136

P(X)=0.25962

c. Would you be surprised if, after observing 18 individuals, fewer than half covered their mouth when sneezing? why?

Solution:

Given that

n=18

p=0.267 (because p is the probability of success which is “number of individuals not covering their mouths when sneezing” in the question)

q=1-0.267=0.733

x=9 (x is the number of successes “number of individuals not covering their mouths when sneezing”, if less than half cover their mouth then more than half will not cover), so let x=9

C_x^n=n!/(n-x)!x!=18!/(18-9)!9!=48620

P(X)=48620×(0.267)^9×〖0.733〗^(18-9)

P(X)=48620×0.00000689×0.0610

P(X)=0.020

Yes, I am surprised that probability of less than 9 individuals covering their mouth when sneezing is 0.020. Which is extremely is small.

3 0

3 years ago