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3 years ago

What is the solution of 5y + 2 = 42?

Mathematics

2 answers:

kozerog [31]3 years ago

8 0

Y=8
Hope this helps, mark brainliest if I helped any!

Vlad1618 [11]3 years ago

4 0

The answer is y = 8 from the photo

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Find thd <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D" id="TexFormula1" title="\frac{dy}{dx}" alt="\frac{dy}{dx}" a

NARA [144]

$x^3y^2+\sin(x\ln y)+e^{xy}=0$

Differentiate both sides, treating $y$ as a function of $x$ . Let's take it one term at a time.

Power, product and chain rules:

$\dfrac{\mathrm d(x^3y^2)}{\mathrm dx}=\dfrac{\mathrm d(x^3)}{\mathrm dx}y^2+x^3\dfrac{\mathrm d(y^2)}{\mathrm dx}$

$=3x^2y^2+x^3(2y)\dfrac{\mathrm dy}{\mathrm dx}$

$=3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}$

Product and chain rules:

$\dfrac{\mathrm d(\sin(x\ln y)}{\mathrm dx}=\cos(x\ln y)\dfrac{\mathrm d(x\ln y)}{\mathrm dx}$

$=\cos(x\ln y)\left(\dfrac{\mathrm d(x)}{\mathrm dx}\ln y+x\dfrac{\mathrm d(\ln y)}{\mathrm dx}\right)$

$=\cos(x\ln y)\left(\ln y+\dfrac1y\dfrac{\mathrm dy}{\mathrm dx}\right)$

$=\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}$

Product and chain rules:

$\dfrac{\mathrm d(e^{xy})}{\mathrm dx}=e^{xy}\dfrac{\mathrm d(xy)}{\mathrm dx}$

$=e^{xy}\left(\dfrac{\mathrm d(x)}{\mathrm dx}y+x\dfrac{\mathrm d(y)}{\mathrm dx}\right)$

$=e^{xy}\left(y+x\dfrac{\mathrm dy}{\mathrm dx}\right)$

$=ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}$

The derivative of 0 is, of course, 0. So we have, upon differentiating everything,

$3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}+\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}+ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}=0$

Isolate the derivative, and solve for it:

$\left(6x^3y+\dfrac{\cos(x\ln y)}y+xe^{xy}\right)\dfrac{\mathrm dy}{\mathrm dx}=-\left(3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}\right)$

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}}{6x^3y+\frac{\cos(x\ln y)}y+xe^{xy}}$

(See comment below; all the 6s should be 2s)

We can simplify this a bit by multiplying the numerator and denominator by $y$ to get rid of that fraction in the denominator.

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^3+y\cos(x\ln y)\ln y-y^2e^{xy}}{6x^3y^2+\cos(x\ln y)+xye^{xy}}$

3 0

3 years ago

I don’t know the answer pls help I’ll give you brainliest!! 19 points.

gladu [14]

Answer:

it is A i think i am a nub tho

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find the diameter of a cicle with an area of 240.48 π square millimeters?

seropon [69]

31.02 mm.

Step-by-step explanation:

Step 1:

The area of the given circle is 240.48 π sq mm

We need to find the diameter of the circle

Step 2:

The formula for obtaining the area of any circle is π*r² where r represents the radius of the circle

We know that the diameter of circle is 2 times its radius.

Hence equating the formula of the area of the circle to the given value we can find its radius. Then multiplying the radius by 2 , we get the diameter.

Step 3 :

Using the above method , we have

πr² = 240.48 π

=> r² = 240.48 π / π = 240.48

=> r = √240.48 = 15.51 approximately

Hence the diameter of the given circle is 2 * 15.51 = 31.02 mm.

6 0

3 years ago

How many labeled points are between points b and u ?

Olenka [21]

Answer:

It is difficult to give a specific answer without your scenario but maybe this may help you out a bit.

Let's say you have a line like the one attached:

I labelled certain points b and u so you can use it as a reference. Now all you need to do is count all the points that lie on the same line and are found between.

In this case it would be point d and point e because the rest of the points do not line on the same line. For this problem particular scenario, the answer would be 2.

7 0

4 years ago

Question 4.

Ludmilka [50]

Answer:

9.80 m

Step-by-step explanation:

The mnemonic SOH CAH TOA is intended to remind you of the relationship between sides of a right triangle and its angles.

<h3>setup</h3>

The geometry of this problem can be modeled by a right triangle, so these relations apply. We are given an angle and adjacent side, and asked for the opposite side, so the relation of interest is ...

Tan = Opposite/Adjacent

Using the given values, we have ...

tan(24°) = AC/AB = (tree height)/(distance from tree)

tan(24°) = AC/(22 m)

<h3>solution</h3>

Multiplying by 22 m gives ...

tree height = AC = (22 m)·tan(24°) ≈ 9.79503 m

The height of the tree is about 9.80 meters.

5 0

2 years ago