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3 years ago

Can anyone help me out on this

Mathematics

1 answer:

Licemer1 [7]3 years ago

4 0

Answer:

y=x+10

Step-by-step explanation:

y=mx+b

y=1x+b

1 because for every 10 it goes to the right, it goes up 10 as well.

b=10 because the function crosses the y-axis at 10

y=x+10

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A fabric store sells close-out fabrics for $2.14 a yard. A customer buys 8 yards of fabric. How much does the customer pay for t

blsea [12.9K]

Answer:

$17.12

Step-by-step explanation:

2.14 · 8 = 17.12

8 0

3 years ago

At the movie theatre, child admission is $6.30 and adult admission is $9.60 . On saturday, twice as many adult tickets as child

joja [24]

Let's assume

number of child tickets sold on saturday is x

number of adult tickets sold on saturday is y

On saturday, twice as many adult tickets as child tickets were sold

so, we get

$y=2x$

child admission is $6.30 and adult admission is $9.60

a total sales of $535.50

we get

$6.30x+9.60y=535.50$

now, we can plug y=2x

$6.30x+9.60*2x=535.50$

now, we can solve for x

$25.5x=535.5$

$x=21$

now, we can find y

$y=2*21$

$y=42$

so,

number of child tickets sold on saturday is 21

number of adult tickets sold on saturday is 42.........Answer

4 0

3 years ago

Triangle ABC is an isosceles triangle in which side

Shkiper50 [21]

Answer:

Option B.

Step-by-step explanation:

Consider the below figure attached with this question.

It is given that triangle ABC is an isosceles triangle.

From the below figure it is clear that the vertices of triangle are A(-2,-4), B(2,-1) and C(3,-4).

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using this formula, we get

$AB=\sqrt{(2-(-2))^2+(-1-(-4))^2}=\sqrt{16+9}=5$

$BC=\sqrt{(3-2)^2+(-4-(-1))^2}=\sqrt{1+9}=\sqrt{10}$

$AC=\sqrt{(3-(-2))^2+(-4-(-4))^2}=\sqrt{25}=5$

Now,

Perimeter of triangle ABC = AB + BC + AC

$=5+\sqrt{10}+5$

$=10+\sqrt{10}$

So, perimeter of triangle ABC is $10+\sqrt{10}$ units.

Therefore, the correct option is B.

4 0

3 years ago

Read 2 more answers

A study was performed to investigate whether teens and adults had different habits when it comes to consuming meat-free meals. I

Elden [556K]

Answer:

H₀ should be rejected at CI 95% .

Then the proportion of adults with 95 % CI is bigger than the proportion of teen

Step-by-step explanation:

From adult sample:

n₂ = 2323

x₂ = 1601

p₂ = 1601 / 2323 p₂ = 0,689 or p₂ = 68,9%

From teen sample:

n₁ = 875

x₁ = 555

p₁ = 555/ 875 p₁ = 0,634 or p₁ = 63,4

Values of p₁ and p₂ suggest that the proportion of adults consuming at least one meat free meal per week is bigger than teen proportion.

To either prove or reject the above statement we have to develop a difference of proportion test according to:

Hypothesis test:

Null Hypothesis H₀ p₁ = p₂

Alternative Hypothesis Hₐ p₂ > p₁

So is a one-tail test to the right

We can establish a confidence interval of 95 % then α = 5 %

or α = 0,05

As the samples are big enough we will develop a z test

Then z(c) for α = 0,05 from z table is z(c) = 1,64

To calculate z(s)

z(s) = ( p₂ - p₁ ) / √p*q* ( 1/n₁ + 1/n₂ )

where p = ( x₁ + x₂ ) / n₁ + n₂ p = 555 + 1601 / 875 + 2323

p = 2156/3198 p = 0,674

and q = 1 - 0,674 q = 0,326

z(s) = ( 0,689 - 0,634 ) / √0,674*0,326 ( 1/875 + 1 / 2323

z(s) = 0,055/ √ 0,2197 ( 0,00114 + 0,00043)

z(s) = 0,055/ √0,2197* 0,00157

z(s) = 0,055/ √ 3,45*10⁻⁴

z(s) = 0,055 / 1,85*10⁻²

z(s) = 5,5/1,85

z(s) = 2,97

Comparing z(s) and z(c) z(s) > z(c)

Then z(s) is in the rejection region we reject H₀.

We can claim that the proportion of adult eating at least one meat-free meal is bigger than the proportion of teen

6 0

3 years ago

Mike and Susie went out to dinner the price of the dinner for them both was $30 they tipped their server 20% of that amount how

photoshop1234 [79]

Answer:

$18

Step-by-step explanation:

20% of 30 is 6.

$18 is half of the total

8 0

3 years ago