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sp2606 [1]
3 years ago
10

What is the volume of 20 ice cubes,each of sides is 5 cm.

Mathematics
1 answer:
xenn [34]3 years ago
6 0

Answer:

2500 cm^3

Step-by-step explanation:

The volume of a cube of side length s is V = s^3.

The volume of this particular cube is V = (5 cm)^3 = 125 cm^3.

The volume of 20 such ice cubes is thus 20(125 cm^3) = 2500 cm^3.

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Three identical fair coins are thrown simultaneously until all three show the same face. What is the probability that they are t
mixer [17]

Answer:

The probability that the coins are thrown more than three times to show the same face is 0.3164.

Step-by-step explanation:

The problem is related to Geometric distribution.

The Geometric distribution defines the probability distribution of <em>X</em> failures before the first success.

The probability distribution function is:

P(X=k)=(1-p)^{k}p;\    k = 0, 1, 2, ...

First compute the probability that in the i^{th} throw all the three coins will show the same face.

P (All the 3 coins shows the same face) = P (All the three coins shows Heads) + P (All the three coins shows Tails)

                      =(\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2} )+(\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2} )\\=\frac{1}{8}+\frac{1}{8}\\  =\frac{2}{8} \\=\frac{1}{4}

Now compute the probability that it takes more than 3 throws for the coins to show the same face.

P (<em>X</em> > 3) = 1 - P (<em>X</em> ≤ 3)

=1-[P(X=1)+P(X=2)+P(X=3)]\\=1-[[(1-\frac{1}{4} )^{0}\times\frac{1}{4}]+[(1-\frac{1}{4} )^{1}\times\frac{1}{4}]+ [(1-\frac{1}{4} )^{2}\times\frac{1}{4}]+[(1-\frac{1}{4} )^{3}\times\frac{1}{4}]]\\=1-[0.2500+0.1875+0.1406+0.1055]\\=1-0.6836\\=0.3164

Thus, the probability that it takes more than 3 throws for the coins to show the same face is 0.3164.

8 0
3 years ago
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umka2103 [35]

Answer:

B

Step-by-step explanation:

-4y-3<9

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y<-3

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Nimfa-mama [501]
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4 years ago
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r-12
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