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2 years ago

Select the step in the solution that FIRST shows an error.

2 answers:

6 0

Step 3 is where it goes wrong first. Step two, you divide both sides of the equation by 4 so 4x/4= just X so it should end at step 3 with just x=5 and don’t continue because then you’re dividing twice.

GalinKa [24]2 years ago

5 0

Step 3 bc step / was off and so step 3 kinda followed along and was actually wrong

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I need the slope of this graph

shtirl [24]

Answer:

3/2

Step-by-step explanation:

Pick two points on the graph

(-1,2) and (3,8)

We can use the slope formula

m= ( y2-y1)/(x2-x1)

= ( 8-2)/(3 - -1)

= (8-2)/(3+1)

= 6/4

= 3/2

6 0

2 years ago

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How can you find the least common denominator for 1/8 and 2/9

FromTheMoon [43]

M a t h w a y to find the answer

5 0

3 years ago

Evaluate 3x+y when x=1/3 and y=−7/4. Write your answer as a fraction in simplest form.

SOVA2 [1]

Answer:

3x+y

=3*1/3-7/4

=1-7/4

=(4-7)/4

=-3/4

6 0

2 years ago

Find 3 consecutive odd integers such that 10 times the first is 59 more than the third?

Nikolay [14]

Answer: The required three consecutive odd integers are 7, 9 , 11.

Step-by-step explanation:

Let x , x+2 , x+4 be the three consecutive odd integers.

As per given ,

10(x) = 59+x+4

⇒10x= 59+x+4

⇒ 9x= 63

⇒ x= 7 [ divide both sides by 7]

Hence, the required three consecutive odd integers are 7, 9 , 11.

7 0

2 years ago

In the adjoining figure, XY = XZ . YQ and ZP are the bisectors of <img src="https://tex.z-dn.net/?f=%20%5Cangle" id="TexFormula1

svetlana [45]

Answer:

See Below.

Step-by-step explanation:

Statements: Reasons:

$1)\, XY=XZ$ Given

$2) \text{ $ m\angle Y= m\angle Z$}$ Isosceles Triangle Theorem

$\displaystyle 3) \text{ $m\angle Y=m\angle XYQ + \angle QYZ$}$ Angle Addition

$\displaystyle 4)\text{ $YQ$ bisects $\angle XYZ$}$ Given

$5) \text{ $m\angle XYQ=m\angle QYZ$}$ Definition of Bisector

$\displaystyle 6)\text{ $m\angle Y=2m\angle QYZ$}$ Substitution

$7)\text{ $m\angle Z=m\angle XZP+m\angle PZY$}$ Angle Addition

$8)\text{ $ZP$ bisects $\angle XZY$}$ Given

$\displaystyle 9) \text{ $m\angle XZP=m\angle PZY$ }$ Definition of Bisector

$\displaystyle 10) \text{ $ m\angle Z = 2m\angle PZY $}$ Substitution

$11)\text{ } 2m\angle QYZ=2m\angle PZY$ Substitution

$12)\text{ }m\angle QYZ=m\angle PZY$ Division Property of Equality

$13)\text{ } YZ=YZ$ Reflexive Property

$14)\text{ } \Delta YZP\cong\Delta ZYQ$ Angle-Side-Angle Congruence*

$15)\text{ } YQ=ZP$ CPCTC

*For clarification:

∠Y = ∠Z

YZ = YZ (or ZY)

∠PZY = ∠QYZ

So, Angle-Side-Angle Congruence:

ΔYZP is congruent to ΔZYQ

5 0

3 years ago

Read 2 more answers