Answer: x=6 y=4
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We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
Hope I was able to help :-)
6(n+8)=2
6n + 48 = 2
6n + 48 - 48 = 2 - 48
6n = -46
N = -46/6
N = -7 2/3
First you would make the mixed fractions into improper fraction by multiplying the denominator and the whole number, then adding the numerator. Then you would flip the second fraction and multiply.
Ex. 1 1/2 ÷1 1/2
1st. 3/2÷3/2
2nd: 3/2×2/3
3rd 3/2x2/3=1
