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raketka [301]
3 years ago
14

Which of the solids above uses the best units

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
8 0

Answer:

I think its A. solid a. most likely

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Write the condition under which the hcf of the given algebraic expression is 1​
solong [7]

Answer:

A HCF is the highest common factor between 2 or more numbers. because every number times 1 is equal to itself, every 2 numbers have a common factor of 1.

HCF between 2 numbers a,b or expressions such that a and b are not equal to 0 , will never be 0 , because of the simple fact that anything times 0 is equal to 0 , and we stated that a,b isn’t equal to 0 , so that’s a contradiction.

Since you stated that there is no common factor bigger or lower than 1 between the 2 numbers (which means that the two numbers are equal to each other and equal to 1 or 0 , think about it yourself a little bit) that means that the only factor is 1 when the two numbers are not 1 , and 0 or anything if the two numbers are 0 , because again, every number times 0 is equal to 0 .

So finally, there is not HCF if the two numbers stated are both 0 , and the only other possibility is for them to be 1 , and in this case, the HCF will be 1 .

6 0
2 years ago
A city pool sells full-day and half-day passes during the summer. The goal is to make $1000 each day from pool pass sales. The g
vampirchik [111]

Answer:

The answer is 200

Step-by-step explanation:

Took the test lol

4 0
3 years ago
A steady wind blows a kite due west. The kite's height above ground from horizontal position x = 0 to x = 80 ft is given by y =
GaryK [48]

Answer:

The distance travelled by the kite is 122.8 ft ( approx )

Step-by-step explanation:

Here, the given function,

y=150-\frac{1}{40}(x-50)^2

Differentiating with respect to x,

y'=-\frac{1}{20}(x-50)

∵ arc length of a curve is,

L=\int_{a}^{b} \sqrt{1+y'^2}dx

Where, y shows the height of the curve for a ≤ x ≤ b,

Thus, the arc length of the given curve is,

L=\int_{0}^{80} \sqrt{1+(-\frac{1}{20}(x-50)^2}dx

Put -\frac{1}{20}(x-50)=tan\theta

\implies -dx=-20 sec^2\theta d\theta

\implies L=-20\int_{0}^{80} \sqrt{1+tan^2\theta}sec^2\theta d\theta

=-20\int_{0}^{80} (sec \theta ) sec^2\theta d\theta

=-20\int_{0}^{80} (sec \theta ) sec^2\theta d\theta

By integration by parts,

=|-\frac{20}{2}(sec \theta tan\theta +ln|sec\theta +tan\theta |) |^{x=80}_{x=0}

If x = 80, tan \theta = -\frac{1}{20}(30-50)=\frac{3}{2}

sec \theta = \frac{\sqrt{13}}{2}

\implies \theta = \frac{1}{20}(0-50)=\frac{5}{2}

sec \theta = \frac{\sqrt{29}}{2}

Thus, the length of the curve is,

=-10(\frac{\sqrt{13}}{2}(-\frac{3}{2}) +ln|\frac{13}{2}-\frac{3}{2}|) + 10(\frac{5\sqrt{29}}{4} + ln |\frac{29}{2} + \frac{5}{2} |)

\approx 122.8\text{ feet}

8 0
3 years ago
Solve the equation using the distributive property and properties of equality.
RoseWind [281]

Answer:

Step-by-step explanation:

As given ,

-5*(a+3) =-55

(-5*a)+(-5*3)= -55

-5a-15= -55

-5a= -55 +15

-5a = -40

a = 8

4 0
3 years ago
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Howard earned $48 in interest after saving for 3 years at a simple annual interest interest rate of 2% how much did Howard origi
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70.05 is how much he deposited 
5 0
3 years ago
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