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Ivahew [28]
3 years ago
15

Trevor has a family photograph that measures 4 inches wide and 6 inches long. He wants to enlarge the photo and hang it on the w

all. if the length of the enlarged photo is 30 inches, what is the width of the enlarged photo?
Mathematics
1 answer:
miskamm [114]3 years ago
8 0

Answer:

20 inches

Step-by-step explanation:

To solve this problem, we need to cross multiply. Lets input the values (4, 6, 30) as shown below:

\frac{4}{6} =\frac{x}{30}

Next we cross multiply. We multiply 4 and 30, and we multiply 6 and <em>x</em>.

4(30) = 120

6(x) = 6x

Now, lets put the values above back into the equation:

6x = 120

Our last step is to divide 120 by 6 to get <em>x </em>by itself.

x= \frac{120}{6}

x=20

The answer is 20 inches.

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4 years ago
Given that sec(0) =25/7<br> and 0 is in Quadrant I, find csc(0) and tan(0).
Phoenix [80]

Answer:

Csc(0)=24/27 and Tan(0)= 24/7

Step-by-step explanation:

We know that secant is the inverse of cos. So that Sec(x) = Cos^-1(x)= hypotenuse/adjacent. We now know that 25 is hypotenuse and 7 is the length of side adjacent to angle theta.

Given this information we can find the length of side opposite to theta, which has length 24.

Now we know:

Hypotenuse=27

Adjacent=7

Opposite=24

Csc is inverse of sin, so that scs=sin^-1=hypotenuse/opposite=27/24

and tan=opposite/adjacent=24/7

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3 years ago
How to write 0.997 as a fraction?
cluponka [151]
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4 years ago
Read 2 more answers
Consider the system of equations.
jok3333 [9.3K]

Given:

The system of equations:

x-3y=9

\dfrac{1}{5}x-2y=-1

To find:

The number that can be multiplied by the second equation to eliminate the x-variable when the equations are added together.

Solution:

We have,

x-3y=9                        ...(i)

\dfrac{1}{5}x-2y=-1       ...(ii)

The coefficient of x in (i) and (ii) are 1 and \dfrac{1}{5} respectively.

To eliminate the variable x by adding the equations, we need the coefficients of x as the additive inverse of each other, i.e, a and -a So, a+(-a)=0.

It means, we have to convert \dfrac{1}{5} into -1. It is possible if we multiply the equation (ii) by -5.

On multiplying equation (ii) by -5, we get

-x+10y=5       ...(iii)

On adding (i) and (iii), we get

7y=14

Here, x is eliminated.

Therefore, the number -5 can be multiplied by the second equation to eliminate the x-variable.

6 0
3 years ago
Solve for a.<br> ab +c= d.
bixtya [17]

Answer:

  a = (d -c)/b

Step-by-step explanation:

Undo the addition of c, by subtracting c.

  ab +c -c = d -c

  ab = d - c

Undo the multiplication by b, by dividing by b.

  ab/b = (d -c)/b

  a = (d -c)/b

5 0
3 years ago
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